Answer: 1020 ways
Step-by-step explanation:
Let C= comedy
Let M= Mystery
Number of movies(comedy) = 10
Number of movies (mystery) = 10
The total number of movies from which selection is to be made is 10 + 10
= 20
We want to pick 3 movies from 10 comedies and 10 mysteries with at least one mystery.
The selection will be from;
Unconditional selection - (0 mysteries)
=unconditional selection - ( all comedy included)
= 20C3 - 10C3 For combination, [nCr = n! /(n-r) r! ]
= [20!/(20-3)!3!] - [10!/(10-3)!3!
= (6840/6) - (720/6)
= 1140 - 120
= 1020 ways
You are able to divide or mutiply both so let's divide. Divide each by four to get1/2. hope this helped.
Answer:
3
Step-by-step explanation:
it adds three every time
Common difference of an Arithmetic progression can be found out by subtracting the preceding term from that given term.
i.e
therefore, the common difference of the above Arithmetic progression is -4 .
