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3 years ago

Help plssss ASAP brainliest

Mathematics

1 answer:

____ [38]3 years ago

8 0

Answer:

Step-by-step explanation:

x and 6

6^2 is 36

x^2 is still x^2

now we need to find the square root of their sum

square root of ( 36 + x^2 )

I'm not that sure about this one i think it might be more simplified

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What is the graph of

horrorfan [7]

Honestly idk you’ll need a better way to explain this

8 0

3 years ago

Martina drove 385 miles in 7 hours. at the same rate, how long would it take her to drive 495 miles?

Anarel [89]

385/7 = 495/x

Answer: 9 hours

5 0

3 years ago

Read 2 more answers

Complex numbers zj and zz are given by zj = 3- j2, zz = - 4 + j3. (a) express zj and zz in polar form. (b) find lz1l by first ap

inna [77]

Solution:

Given: zj = 3- j2, zz = - 4 + j3

Part a:

zj = 3- j2 = $3.6e^{-j33.7^{\circ}}$

zz = - 4 + j3 = $5e^{j143.1^{\circ}}$

Part b:

|zj| = |3− j2| = √3² +(−2)² = √13 = 3.60

|z1| = √(3− j2)(3+ j2) = √ 13 = 3.60.

Part c:

With the help of part a:

z1z2 = $3.6e^{-j33.7^{\circ}}.5e^{j143.1^{\circ}}$

6 0

3 years ago

A random sample of 20 students yielded a mean of ¯x = 72 and a variance of s2 = 16 for scores on a college placement test in mat

Helen [10]

Answer:

The 98% confidence interval for the variance in the pounds of impurities would be $8.400 \leq \sigma^2 \leq 39.827$ .

Step-by-step explanation:

1) Data given and notation

$s^2 =16$ represent the sample variance

s=4 represent the sample standard deviation

$\bar x$ represent the sample mean

n=20 the sample size

Confidence=98% or 0.98

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case the sample variance is given and for the sample deviation is just the square root of the sample variance.

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=20-1=19$

Since the Confidence is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and we can use excel, a calculator or a table to find the critical values.