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Nataly [62]
3 years ago
10

What is the common difference of the sequence 8, 4, 0, -4, -16?

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
7 0

\large \mathfrak{Solution : }

Common difference of an Arithmetic progression can be found out by subtracting the preceding term from that given term.

i.e

  • common \:  \: difference = 4 - 8
  • common \:  \: difference =  - 4

therefore, the common difference of the above Arithmetic progression is -4 .

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Write the percent as a fraction 77.5%
zysi [14]
77.5%

Change to decimal:-

77.5 ÷ 100 = 0.775

775/1000

31/40

77.5% = 31/40
6 0
3 years ago
What is the value of the 0 in 3.06
Dominik [7]
Well actually that is in the value place of the tenths not tens.
4 0
3 years ago
Find the value of x and y from ordered pair.<br>(x+y,2x-y)=(13,2)​
Katarina [22]

Answer:

x=5, y=8

Step-by-step explanation:

x+y=13

2x-y=2

add these two equations

3x=15

therefore x=5

apply this value in x+y=13

5+y=13

then y=13-5 = 8

8 0
3 years ago
Read 2 more answers
Joann has a jug containing 128 ounces of milk. She drinks 14 ounces of milk each day. Enter the function f(x) that represents th
Tatiana [17]

Answer:

f(x)=128-14x

Step-by-step explanation:

So, we started out with 128 ounces of milk.

Each day, Joann drinks 14 ounces of milk.

Therefore, the amount of milk left over after x days is 14 times x subtracted from 128.

Therefore, our function is:

f(x)=128-14x

And we're done!

6 0
3 years ago
A certain firm has plants A, B, and C producing respectively 35%, 15%, and 50% of the total output. The probabilities of a non-d
Sliva [168]

Answer:

There is a 44.12% probability that the defective product came from C.

Step-by-step explanation:

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

-In your problem, we have:

P(A) is the probability of the customer receiving a defective product. For this probability, we have:

P(A) = P_{1} + P_{2} + P_{3}

In which P_{1} is the probability that the defective product was chosen from plant A(we have to consider the probability of plant A being chosen). So:

P_{1} = 0.35*0.25 = 0.0875

P_{2} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

P_{2} = 0.15*0.05 = 0.0075

P_{3} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

P_{3} = 0.50*0.15 = 0.075

So

P(A) = 0.0875 + 0.0075 + 0.075 = 0.17

P(B) is the probability the product chosen being C, that is 50% = 0.5.

P(A/B) is the probability of the product being defective, knowing that the plant chosen was C. So P(A/B) = 0.15.

So, the probability that the defective piece came from C is:

P = \frac{0.5*0.15}{0.17} = 0.4412

There is a 44.12% probability that the defective product came from C.

3 0
3 years ago
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