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Artemon [7]
3 years ago
6

steve runs a car wash and detail shop. he determines that 50% of customers get their car washed and vacuumed, while 72% get thei

r car washed. what is the probability that a customer will get their car vacuumed given that they are getting it washed? (in decimal form rounded to nearest thousandths)​
Mathematics
1 answer:
3241004551 [841]3 years ago
8 0

Answer:

The probability is 0.694

Step-by-step explanation:

Let the probability of getting a car washed be

P(W) = 72% = 0.72

Let the probability of getting a car vacuumed be

P(V) = ?

Probability of getting car washed and vacuumed is P(W n V) = 50% = 0.5

From Bayes’ theorem

P(V|W) is the probability that a customer gets their car vacuumed given that they are getting it washed

So mathematically;

P(V|W) = P(V n W)/P(W)

= 0.5/0.72 = 0.694

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Answer:

Grades between 62 and 64 result in a D grade.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

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16th percentile:

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X - 71.9 = -0.995*7.8

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X - 71.9 = -1.28*7.8

X = 62

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