The value of result of the code segment is executed is known to be 4.
<h3>Why is the value of the code segment so?</h3>
When the result of is not executed because the condition is said to be false and also when there is a false condition is, the else statement will be said to be true
Therefore, result = result + 2; -> result is brought up by 2 to bring about 4 and as such, the value of result of the code segment is executed is known to be 4.
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Answer:
The program to this question can be given as:
Program:
#include <stdio.h> //include header files
#include<math.h>
int main() //main method
{
double treeHeight = 0.0; //declare variables
and assign value
double shadowLength = 0.0;
double angleElevation = 0.11693706;
// (0.11693706 radians = 6.7 degrees) convert number into angle.
shadowLength = 17.5;
treeHeight = shadowLength * tan(angleElevation); //convert number into angle
printf("Tree height: %lf\n", treeHeight); //print value.
return 0;
}
Output:
Tree height: 2.055778
Explanation:
In the above C language program firstly we include the headers. In this header file, we include a (math.h) header file this file helps to use the math function. Then we declare the main method in the main method we declare the variable that is given in the question that are treeHeight, shadowLength , angleElevation. All the variable datatype is double because it stores the floating-point value. Then we apply the formula that is treeHeight = shadowLength * tan(angleElevation). In this formula, the treeHeight variable holds the value. Then we print the variable value for print the double value we use the lf(that is long float).
Answer:
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