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Serga [27]
3 years ago
8

Two tongue-rollers have 12 children. 8 of their children can roll their tongues and 4 cannot. Make an argument about the genotyp

e of each of the parents and use a punnett square to explain your reasoning.
Biology
2 answers:
uranmaximum [27]3 years ago
6 0
Let  the  dominant gene  for  tongue rolling  be  R  while  the  receive gene  be r. Therefore the  genotype  of  the  parent  is  heterogeneous  that  Rr  x Rr  since   they are  having  children  who  are  not  able  to  roll  the  tongue.The  punnet   square  is  as  follows.
Nezavi [6.7K]3 years ago
5 0
<span>If capital T is dominant trait of tongue-rolling, then little t is recessive trait of no-tongue rolling. For 8 children to roll their tongues (TT or Tt) and 4 children who can't (tt) both parents must be heterozygous (Tt).</span>
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Answer:

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3 years ago
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Gelneren [198K]

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7 0
1 year ago
First identify the gametes. use pink labels to identify the male and female gamete types and white labels to identify the gamete
Lady bird [3.3K]
I found the whole exercise on the internet. Attached is the scheme with labels for the gametes, f2 generation, and respective frequencies.

For the gametes position, on the left pink square on the male gametes side you should put a capital G, <span>and on the right pink square on the male gametes side you should put a small g, as</span> the only two possible offsprings that are showing is "GG" under the left male gamete and "gg" under the right male gamete. On the top pink square on the female gametes side you should put a capital G, and on the bottom pink square on the female gametes side you should put a small g, as the only two possible offsprings that are showing is "GG" on the same line as the top female gamete and "gg" on the same line as the bottom female gamete.
As for the frequencies of the gametes, you should put the white label that marks 1/2 by the side of each gamete.
Related to the F2 generation, the top right and bottom left pink squares should have the label with a capital G and small g - "Gg" which reflects the combination of the male gamete on its line with the female gamete also on its line.
As for the frequencies of the progeny, each of the genotypes formed from the union of the gametes should have by the side the white label that marks 1/4.
The totals would be that GG is 1/4, Gg is 1/2 (1/4+1/4), and gg is also 1/4.

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