Question

Please help !!

Answer 1

Given:

The limit problem is:

$\lim_{x\to 3}(x^2+8x-2)$

To find:

The limit of the function by using direct substitution.

Solution:

We have,

$\lim_{x\to 3}(x^2+8x-2)$

Applying limit, we get

$\lim_{x\to 3}(x^2+8x-2)=(3)^2+8(3)-2$

$\lim_{x\to 3}(x^2+8x-2)=9+24-2$

$\lim_{x\to 3}(x^2+8x-2)=33-2$

$\lim_{x\to 3}(x^2+8x-2)=31$

Therefore, the correct option is D.