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const2013 [10]
3 years ago
6

DUE RIGHT NOW!!!!! PLEASE HELP!!!!!

Mathematics
1 answer:
elixir [45]3 years ago
6 0
Gfurknegwuwn nakwubwkw. Jahsken
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8c=5c+21 What would that be
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To solve for C, you have to get both of the numbers with a C on the same side.  So, subtract the 5c from the right side onto the left side.

8c = 5c + 21\\8c - 5c = 5c - 5c + 21\\3c = 21

Then, divide by 3 on each side.

3c = 21\\3c /3 = 21/3\\c = 7

So, c = 7.
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3 years ago
The SAT is standardized to be normally distributed with a mean µ = 500 and a standard deviation σ = 100. What percentage of SAT
Aliun [14]

Answer:

34.134%

68.268%

Step-by-step explanation:

Given that:

Mean (m) = 500

Standard deviation (s) = 100

Percentage between 500 and 600

P(500 < x < 600)

P(x < 600) - P(x < 500)

Z = (x - m) / s

P(x < 600)

Z = (600 - 500) /100 = 1

P(x < 500)

Z = (500 - 500) / 500 = 0

P(Z< 1) - P(Z < 0)

0.84134 - 0.5

= 0.34134

= 0.34134 * 100%

= 34.134%

B.) Between 400 and 600

P(x < 400)

Z = (400 - 500) /100 = - 1

P(x < 600)

Z = (600 - 500) / 500 = 1

P(Z< 1 ) - P(Z < - 1)

0.84134 - 0.15866

= 0.68268

= 0.68268 * 100%

= 68.268%

8 0
3 years ago
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