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4 years ago

11

Tony needs 16 inch-long pieces of gold chain to make each of 3 necklaces. He has a piece of chain that is feet long. How much ch

ain will he have left after making the necklaces?

1 answer:

Lynna [10]4 years ago

5 0

Yikes idkAnswer:

Step-by-step explanation:

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The equation (x + 6)^2 + (y + 4)^2 = 36 models the position and range of the source of a radio signal. Describe the position of

Ilia_Sergeevich [38]

Answer:

position: (-6, -4)

range: 6

Step-by-step explanation:

The equation is that of a circle centered at (-6, -4) with a radius of √36 = 6. We presume that the "position" is that of the circle's center, and the "range" is the radius of the circle.

___

The standard form equation of a circle with center (h, k) and radius r is ...

(x -h)^2 +(y -k)^2 = r^2

Matching parts of the equation, we find ...

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3 years ago

Rewrite 5 3/7 as an improper fraction.

bija089 [108]

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3 years ago

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Nikitich [7]

Divide both sides by 0.32 and you'll get the value for c

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3 years ago

Let f(x) = tan(x) - 2/x. Let g(x) = x^2 + 8. What is f(x)*g(y)?

Tema [17]

Answer:

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

Step-by-step explanation:

We are given that

$f(x)=tan(x)-\frac{2}{x}$

$g(x)=x^2+8$

We have to find $f(x)\times g(y)$

To find the value of $f(x)\times g(y)$ we will multiply f(x) by g(y)

$g(y)=y^2+8$

Now,

$f(x)\times g(y)=(tanx-\frac{2}{x})(y^2+8)$

$f(x)\times g(y)=tan(x)(y^2+8)-\frac{2}{x}(y^2+8)$

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

Hence,

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

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3 years ago

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Okay I can help you with your math!!

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