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3 years ago

11

Tony needs 16 inch-long pieces of gold chain to make each of 3 necklaces. He has a piece of chain that is feet long. How much ch

ain will he have left after making the necklaces?

1 answer:

Lynna [10]3 years ago

5 0

Yikes idkAnswer:

Step-by-step explanation:

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The triangle below is an equilateral triangle. Find y.<br> 10<br> y+3

Colt1911 [192]

Answer:

y = 7

Step-by-step explanation:

An equilateral triangle has all its sides to be equal..

so.

10 = x

10 = y + 3

y = 10 - 3

y = 7

6 0

3 years ago

in exercises 15-20 find the vector component of u along a and the vecomponent of u orthogonal to a u=(2,1,1,2) a=(4,-4,2,-2)

Nimfa-mama [501]

Answer:

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

Step-by-step explanation:

Let $\vec u$ and $\vec a$ , from Linear Algebra we get that component of $\vec u$ parallel to $\vec a$ by using this formula:

$\vec u_{\parallel \,\vec a} = \frac{\vec u \bullet\vec a}{\|\vec a\|^{2}} \cdot \vec a$ (Eq. 1)

Where $\|\vec a\|$ is the norm of $\vec a$ , which is equal to $\|\vec a\| = \sqrt{\vec a\bullet \vec a}$ . (Eq. 2)

If we know that $\vec u =(2,1,1,2)$ and $\vec a=(4,-4,2,-2)$ , then we get that vector component of $\vec u$ parallel to $\vec a$ is:

$\vec u_{\parallel\,\vec a} = \left[\frac{(2)\cdot (4)+(1)\cdot (-4)+(1)\cdot (2)+(2)\cdot (-2)}{4^{2}+(-4)^{2}+2^{2}+(-2)^{2}} \right]\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\frac{1}{20}\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

Lastly, we find the vector component of $\vec u$ orthogonal to $\vec a$ by applying this vector sum identity:

$\vec u_{\perp\,\vec a} = \vec u - \vec u_{\parallel\,\vec a}$ (Eq. 3)

If we get that $\vec u =(2,1,1,2)$ and $\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$ , the vector component of $\vec u$ is:

$\vec u_{\perp\,\vec a} = (2,1,1,2)-\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

$\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

4 0

3 years ago

Jamie ordered 24 combo meals for $5 each for a party. The service charge for home delivery for the whole purchase was $6.

Agata [3.3K]

It's easy you do 24 times 5 and then find out the service charge by dividing ratios between the meal and parties and then add 6$ to your total!

7 0

3 years ago

HELP OR NO PRESENTS FOR YOU

Grace [21]

Answer:

g= (9,8) f= (-5,1)

Step-by-step explanation:

you're welcome =)

7 0

3 years ago

a store buys shirts for $12 each and marks up the price by %25. what is the price for a shirt at this store??

iren [92.7K]

Answer:

15

Step-by-step explanation:

12 x 0.25= 3

12+3=15

8 0

2 years ago