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cestrela7 [59]
3 years ago
5

Three major segments of the transportation industry are motor carriers, such as YRC Worldwide (YRCW); railroads, such as Union P

acific (UNP); and transportation logistics services, such as C.H. Robinson Worldwide, Inc. (CHRW). Financial statement information for these three companies follows (in thousands):
YRC Union Pacific C.H. Robinson
Sales $4,697,500 $19,941,000 $13,144,413
Average total assets 1,824,700 55,159,000 3,436,058
Determine the asset turnover for all three companies.
Business
1 answer:
erma4kov [3.2K]3 years ago
4 0

Answer and Explanation:

The computation of the asset turnover for all three companies is as follows:

<u>Particulars        YRC            UNP                CH </u>

Sales                4697500    19941000          13144413

Divided by

Average

total assets     1824700       55159000          3436058

Assets turnover  2.6                0.4                    3.8

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Heather is sixteen but looks much older. She goes into a jewelry store and buys a diamond bracelet with the money she has been s
patriot [66]

Answer:

can return the bracelet and get her money back

Explanation:

Minors have a restriction on the products that they can. To purchase these products they must have consent of their parent or guardian.

An identity card is required to determine the age of the buyer to avoid wrong sales to minors.

Items prohibited from sale to minors include: alcohol, tobacco, petrol, offensive weapons, intoxicating substances, and expensive jewelry.

So in this scenario since due diligence was not carried out by the store to check Heather's age on purchase, she can return the diamond bracelet and get back her money.

This was an illegal sale.

3 0
3 years ago
Identify each of the following statements about linear programming problems as true or false, and then justify your answer.
nika2105 [10]

Answer and Explanation:

a. The given statement is true as the corner point at the objective function should be feasible solution which is no longer as compared with the value for every adjacent CPF solution as compared with its optimal

b. The given statement is false as the solution can be an edge

c. The given statement is true as it shows the direct relation between the two things

3 0
3 years ago
A vending​ machine's coin box contains​ nickels, dimes, and quarters. The total number of coins in the box is 284. The number of
solong [7]

Answer:

there are 59 nickels, 12 quarters, and 213 dimes

Explanation:

  • let n = nickels
  • let q = quarters
  • let d = dimes

first step:

d = 3 (n + q) = 3n + 3q

d + n + q = 284

0.10d + 0.05n + 0.25q = 27.25

second step:

3n + 3q + n + q = 284

0.10 (3n + 3q) + 0.5n + 0.25q = 27.25

third step:

4n + 4q = 284

0.3n + 0.3q + 0.05n + 0.25q = 27.25

fourth step:

n + q = 71

0.35n + 0.55q = 27.25

fifth step:

replace q = 71 - n

0.35n + 0.55(71 - n) = 27.25

sixth step:

0.35n + 39.05 - 0.55n = 27.25

seventh step:

11.8 = 0.2n

eighth step:

n = 59

q = 71 - 59 = 12

d = 284 - n - q = 284 - 59 - 12 = 213

6 0
3 years ago
The auto repair shop of Quality Motor Company uses standards to control the labor time and labor cost in the shop. The standard
GarryVolchara [31]

Answer:

1. Actual Hour = 145 hour

2. Actual rate per hour = 28.17 per hour

Explanation:

According to the scenario, computation of the given data are as follow:-

1). Labor Efficiency Variance= Labor Rate Variance + Labor Spending Variance

= 170 + 120

= 290

Labor Efficiency Variance = Standard Rate × (Standard Hour - Actual Hour)

-290 = 29 × (54 × 2.5-X)  

-290 = 29 × (135 - X)

-290 = 3,915 - 29x

29x = 4,205

X = 4205 ÷ 29 = 145

Actual Hour = 145 hour

2). Labor Rate Variance = Actual Hour × (Standard Rate-Actual Rate)

120 = 145(29-x)

120 = 4,205-145x

145x = 4,085

X= 4,085 ÷ 145

Actual rate per hour = 28.17 per hour

8 0
3 years ago
If a student attends every management science class, the probability of passing the course is 0.80; but if the student only atte
goldfiish [28.3K]

Answer:

EV of node 4 = 0.6×5 + 0.4×0 = 3

EV of node 5 = 0.1×5 + 0.9×0 = 0.5

EV of node 2 = (0.8×5 + 0.2×EV of node 4) - 3

EV of node 2 = (0.8×5 + 0.2×3 ) - 3

EV of node 2 = 4.6 - 3

EV of node 2 = 1.6

EV of node 3 = (0.5×5 + 0.5×EV of node 5) - 1

EV of node 3 = (0.5×5 + 0.5×0.5 ) - 1

EV of node 3 = 2.75 - 1

EV of node 3 = 1.75

EV of node 3 is higher, therefore, best attend pattern is to attend randomly.

4 0
3 years ago
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