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dsp73
2 years ago
13

PLEASE HELP ! I need this grade . For each equation, tell whether it is always, sometimes, or never true. Explain your reasoning

by showing your steps or using words.
a) 5 - 22 = 6
b) y + 5 =
9+10
2
c) 3.c + 7 = 3 (x + 1)
d) 5x-1=9

Mathematics
1 answer:
QveST [7]2 years ago
5 0
Look it up on google
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The number of donuts produced by a machine is directly proportional to the time the machine runs . The machine produces 380 donu
mrs_skeptik [129]

Answer:

855 donuts

Step-by-step explanation:

380/20 = 19 donuts per minute

19 × 45 = 855

5 0
3 years ago
Please help me asap!!!
Westkost [7]

Answer: immma guess that its c

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Step-by-step explanation:

7 0
3 years ago
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Write out the first 5 outpouts of g(x)=2^x starting with G(1). If only you knew that the value of g(15) how would you determine
gtnhenbr [62]

The first 5 outputs are:

\begin{array}{c|c}x&2^x\\1&2\\2&4\\3&8\\4&16\\5&32\end{array}

As you can see, the outputs keep doubling each time we increment x by 1.

This can be written formally, observing that if you know the value of 2^x, the next value will be

2^{x+1}=2^x\cdot 2

So, again, we've shown that the next value is twice the previous one, so you have

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4 0
3 years ago
brenda savings account principal 850, 5.5% annual interest rate and is compounded quarterly for 1 year. what is the compound int
Sedbober [7]
A = $ 861.69

Equation:
A = P(1 + rt)
Calculation:
First, converting R percent to r a decimal
r = R/100 = 5.5%/100 = 0.055 per year,
putting time into years for simplicity,
1 quarters ÷ 4 quarters/year = 0.25 years,
then, solving our equation

A = 850(1 + (0.055 × 0.25)) = 861.6875 
A = $ 861.69

The total amount accrued, principal plus interest,
from simple interest on a principal of $ 850.00
at a rate of 5.5% per year
for 0.25 years (1 quarters) is $ 861.69.
3 0
2 years ago
Does the data below describe a linear, quadratic, or exponential function?
laiz [17]

Answer:

Linear

Step-by-step explanation:

all values for y have a constant difference of -4.

That makes it linear due to a constant difference

6 0
2 years ago
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