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nadezda [96]
3 years ago
6

A certain television is advertised as a 90- inch Tv ( the diagonal length).

Mathematics
1 answer:
vazorg [7]3 years ago
7 0

Answer:

The width is 64.3 inches

Step-by-step explanation:

Given

d = 90 --- diagonal

h = 63 --- height

Required

Determine the width (w) of the TV

To do this, we make use of Pythagoras theorem which is illustrated as:

d^2 = h^2 + w^2

So, we have:

90^2 = 63^2 + w^2

Evaluate all squares

8100 = 3969 + w^2

Collect like terms

w^2 = 8100 - 3969

w^2 = 4131

Take positive square roots of both sides

w = \sqrt{4131

w = 64.3 -- approximated

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Step-by-step explanation:

x= 9+7 =16

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Use the image below to answer the following question. Find the value of sin x° and cos y°. What relationship do the ratios of si
Inessa [10]

Using relations in a right triangle, it is found that:

  • \sin{x} = \frac{6}{10} = 0.6
  • \cos{y} = \frac{6}{10} = 0.6
  • Since x and y are complementary angles, we have that sin(xº) = cos(yº).

<h3>What are the relations in a right triangle?</h3>

The relations in a right triangle are given as follows:

  • The sine of an angle is given by the length of the opposite side to the angle divided by the length of the hypotenuse.
  • The cosine of an angle is given by the length of the adjacent side to the angle divided by the length of the hypotenuse.
  • The tangent of an angle is given by the length of the opposite side to the angle divided by the length of the adjacent side to the angle.

The hypotenuse in this problem is given as follows:

h^2 = 6^2 + 8^2

h = \sqrt{100}

h = 10.

The sine of x is:

\sin{x} = \frac{6}{10} = 0.6

The cosine of y is:

\cos{y} = \frac{6}{10} = 0.6

Since x and y are complementary angles, we have that sin(xº) = cos(yº).

More can be learned about relations in a right triangle at brainly.com/question/26396675

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8 0
2 years ago
Please help meeee ………..
Len [333]

Answer:

  x = 5

Step-by-step explanation:

The equality of bases property says powers of the same base will be equal if and only if the powers are equal. This property is used to solve exponential equations.

<h3>Application</h3>

  \dfrac{(2)^x}{2}=16\qquad\text{copy of the original equation}\\\\2\times\dfrac{(2)^x}{2}=2\times16\qquad\text{multiply by 2 to isolate the base}\\\\2^x=32\qquad\text{simplify}\\\\2^x=2^5\qquad\text{rewrite the constant as a power of 2}\\\\\boxed{x=5}\qquad\text{use the Equality of Bases Property}

__

<em>Additional comment</em>

Equating the exponents is fully equivalent to taking the logarithm of both sides of the equation, to that base.

  \log_2(2^x)=\log_2(2^5)\ \Longrightarrow\ x=5

6 0
2 years ago
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