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1 answer:
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Question:
A cinema can hold 270 people at one performance 5/9 of the seats were occupied of the occupied seats 40% we occupied by concessionary ticket holders.
What is the number of seats occupied by concessionary ticket holders?.
Answer:
60 seats
Step-by-step explanation:
Given
Number of seats = 270
Occupied Seats = 5/9
Concessionary ticket holders = 40% of occupied Seats
Required
The number of seats occupied by concessionary ticket holders
First the number of occupied seat has to be calculated.
Next is to determine the number of seats occupied by concessionary ticket holders.
Convert percentage to decimal
<em>Hence, 60 seats were occupied by concessionary ticket holders.</em>
Answer:
The interval that describes how long it takes for passengers to board the middle 95% of the time is between 40.16 minutes and 55.84 minutes.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
.
Which interval describes how long it takes for passengers to board the middle 95% of the time?
This is between the 2.5th percentile and the 97.5th percentile.
So this interval is the value of X when Z has a a pvalue of 0.025 and the value of X when Z has a pvalue of 0.975
Lower Limit
Z has a pvalue of 0.025 when . So
Upper Limit
Z has a pvalue of 0.975 when . So
The interval that describes how long it takes for passengers to board the middle 95% of the time is between 40.16 minutes and 55.84 minutes.