9514 1404 393
Answer:
6
Step-by-step explanation:
If 60% are yellow, the other 40% are green. Then the difference between yellow and green is 60% -40% = 20% of the total number of fish. That difference also happens to be half of the number of green fish:
20% = (1/2)(40%)
So, the number of green fish is 2×3 = 6.
_____
If you wanted to, you could write a couple of equations:
y - g = 3
y = 0.60(y +g)
Using the first equation to write an expression for y, we get ...
y = g +3
Using this in the second equation, we have ...
g +3 = 0.6(g +3 +g)
g +3 = 1.2g +1.8 . . . . eliminate parentheses
1.2 = 0.2g . . . . . . . . subtract g+1.8
1.2/0.2 = g = 6 . . . . . divide by 0.2
There are 6 green fish in the aquarium.
Answer:
B
Step-by-step explanation:
Because i said so
Answer:
c = 53 yd is the answer.
Step-by-step explanation:
a = 45 yd
b = 28 yd
c = ?
According to the Pythagorean Theorem,
a² + b² = c²
45² + 28² = c²
2025 + 784 = c²
c² = 2809
c = 53 yd
∴ The dog runs 53 yd
Answer:
H0 : μ1 - μ2 = 0
H1 : μ1 - μ2 ≠ 0
-1. 34
0.1837
Step-by-step explanation:
Full time :
n1 = 125
x1 = 2.7386
s1 = 0.65342
Part time :
n2 = 88
x2 = 2.8439
s2 = 0.49241
H0 : μ1 - μ2 = 0
H1 : μ1 - μ2 ≠ 0
Test statistic :
The test statistic :
(x1 - x2) / sqrt[(s1²/n1 + s2²/n2)]
(2.7386 - 2.8439) / sqrt[(0.65342²/125 + 0.49241²/88)]
−0.1053 / sqrt(0.0034156615712 + 0.0027553)
-0.1053 /0.0785554
= - 1.34
Test statistic = - 1.34
The Pvalue :
Using df = smaller n - 1 = 88 - 1 = 87
Pvalue from test statistic score ;
Pvalue = 0.1837
Pvalue > α ; We fail to reject the null and conclude that the GPA does not differ.
At α = 0.01 ; the result is insignificant
Sry not sure this one is very confusing
