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crimeas [40]
3 years ago
14

Can I get help finshing all these qustions 1. -4(6) 2. -21-8) 3. 121-4) 4. -6(5) 5. -10(-9) 6. -(5) 7. (-5) 8. -30(5) 9. 20(-6)

10. -14(-6) 11. (-13)2 12. –7(15) 13. -3(4) 14. 7(-3) 15. 3(-3) 16. -2(-10) 17. (-5)(-3)(4) 18. -3(-3)(4) 19. -3(-5) 20. 5(-3) 21. 7(-5)(4) 22. -2(-5)(-3) 23. – 10(-3) 24. -21-3)
Mathematics
1 answer:
Papessa [141]3 years ago
8 0

Answer:

1. -4(6)= -24

2.-21-8= -29

3. 121-4 =117

4. -6(5) =-30

5. -10(-9)= 90

6. (-5)7= -35

7. (-5)8= -40

8. -30(5)= -150

9. 20(-6)= -120

10. -14(6)= -84

11. (-13)2 = -26

12. –7(15) = -105

13. -3(4) = -12

14. 7(-3) = -21

15. 3(-3) = -9

16. -2(-10) = 20

17. (-5)(-3)(4) = 60

18. -3(-3)(4)= 36

19. -3(-5) = 15

20. 5(-3) = -15

21. 7(-5)(4) = -140

22. -2(-5)(-3)= -30

23. – 10(-3)=30

24. -21-3= -24

Explanation:

We have followed the rules in adding and subtracting negative as well as positive values on the number line.

When adding two negative values, the result is a negative value.

When adding a negative and positive value, the result is either a positive or negative value depending on if the negative value is bigger or smaller than the positive value

When multiplying two negative values, the result is a positive value

When multiplying one negative and one positive value, the result is a negative value

To make you understand addition and subtraction of negative and positive numbers better, let us use a simple analogy. Assuming you are owing five oranges(-5) and you are only able to give two oranges(+2), you will still be owing 3 oranges(-3). Assuming also that you are owing 6 oranges(-6) and you are able to give 8 oranges(+8), you would have given excess oranges and would be owed two oranges(+2). Hence the results above.

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Stella [2.4K]

Answer:

Anything that does not cost more than $2,560.00

Step-by-step explanation:

Provided that Nikita is spending money that she had invested and the amount  she collected over the period of 7 years. She can buy any item that costs no more than $2,560.00 but how?

It is a problem of simple interest:

Here the principal amount (P) = $2,000.00

Interest rate (r) = 4%

Time period (t) = 7 years

So, total amount that she would get by the end of 7 years is:

A=P+SI

SI=\frac{P\times r\times t}{100}

Plugging the values we get:

SI=\frac{2000\times 4\times 7}{100}=560.00

So the interest collected over 7 years is $560.00

Therefore, the total amount after 7 years is:

\$2000.00+\$560.00=\$2,560.00

If Nikita is using this money then the most expensive item that she could buy will cost no more than $2,560.00.

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3 years ago
Which are counterexamples?<br> Look at the picture below. <br> Choose all that apply.
Flauer [41]

Answer:

x^4/(2x^6)

Explanation:

In the first example the division results in a radical, not a polynomial.

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8 0
3 years ago
What is the volume of a cylinder, in cubic centimeters, with a height of 2 centimeters
harina [27]

Answer:

<h2>         V ≈ 628.3 cm³</h2>

Step-by-step explanation:

Volume of cylinder:  V = π×r² × h

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h = 2 cm

Volume:

V = π×(10)²×2 = 200π cm³ = 628.318.... cm³ ≈ 628.3 cm³

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3 years ago
Henry paid $84 for 3 shirts. each shirt costs the same amount. let s represent the cost of each shirt. solve the equation 3s=84
KengaRu [80]
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4 0
3 years ago
A box with a rectangular base and open top must have a volume of 128 f t 3 . The length of the base is twice the width of base.
noname [10]

Answer:

Width = 4ft

Height = 4ft

Length = 8ft

Step-by-step explanation:

Given

Volume = 128ft^3

L = 2W

Base\ Cost = \$9/ft^2

Sides\ Cost = \$6/ft^2

Required

The dimension that minimizes the cost

The volume is:

Volume = LWH

This gives:

128 = LWH

Substitute L = 2W

128 = 2W * WH

128 = 2W^2H

Make H the subject

H = \frac{128}{2W^2}

H = \frac{64}{W^2}

The surface area is:

Area = Area of Bottom + Area of Sides

So, we have:

A = LW + 2(WH + LH)

The cost is:

Cost = 9 * LW + 6 * 2(WH + LH)

Cost = 9 * LW + 12(WH + LH)

Cost = 9 * LW + 12H(W + L)

Substitute: H = \frac{64}{W^2} and L = 2W

Cost =9*2W*W + 12 * \frac{64}{W^2}(W + 2W)

Cost =18W^2 +  \frac{768}{W^2}*3W

Cost =18W^2 +  \frac{2304}{W}

To minimize the cost, we differentiate

C' =2*18W +  -1 * 2304W^{-2}

Then set to 0

2*18W +  -1 * 2304W^{-2} =0

36W - 2304W^{-2} =0

Rewrite as:

36W = 2304W^{-2}

Divide both sides by W

36 = 2304W^{-3}

Rewrite as:

36 = \frac{2304}{W^3}

Solve for W^3

W^3 = \frac{2304}{36}

W^3 = 64

Take cube roots

W = 4

Recall that:

L = 2W

L = 2 * 4

L = 8

H = \frac{64}{W^2}

H = \frac{64}{4^2}

H = \frac{64}{16}

H = 4

Hence, the dimension that minimizes the cost is:

Width = 4ft

Height = 4ft

Length = 8ft

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3 years ago
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