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crimeas [40]
3 years ago
14

Can I get help finshing all these qustions 1. -4(6) 2. -21-8) 3. 121-4) 4. -6(5) 5. -10(-9) 6. -(5) 7. (-5) 8. -30(5) 9. 20(-6)

10. -14(-6) 11. (-13)2 12. –7(15) 13. -3(4) 14. 7(-3) 15. 3(-3) 16. -2(-10) 17. (-5)(-3)(4) 18. -3(-3)(4) 19. -3(-5) 20. 5(-3) 21. 7(-5)(4) 22. -2(-5)(-3) 23. – 10(-3) 24. -21-3)
Mathematics
1 answer:
Papessa [141]3 years ago
8 0

Answer:

1. -4(6)= -24

2.-21-8= -29

3. 121-4 =117

4. -6(5) =-30

5. -10(-9)= 90

6. (-5)7= -35

7. (-5)8= -40

8. -30(5)= -150

9. 20(-6)= -120

10. -14(6)= -84

11. (-13)2 = -26

12. –7(15) = -105

13. -3(4) = -12

14. 7(-3) = -21

15. 3(-3) = -9

16. -2(-10) = 20

17. (-5)(-3)(4) = 60

18. -3(-3)(4)= 36

19. -3(-5) = 15

20. 5(-3) = -15

21. 7(-5)(4) = -140

22. -2(-5)(-3)= -30

23. – 10(-3)=30

24. -21-3= -24

Explanation:

We have followed the rules in adding and subtracting negative as well as positive values on the number line.

When adding two negative values, the result is a negative value.

When adding a negative and positive value, the result is either a positive or negative value depending on if the negative value is bigger or smaller than the positive value

When multiplying two negative values, the result is a positive value

When multiplying one negative and one positive value, the result is a negative value

To make you understand addition and subtraction of negative and positive numbers better, let us use a simple analogy. Assuming you are owing five oranges(-5) and you are only able to give two oranges(+2), you will still be owing 3 oranges(-3). Assuming also that you are owing 6 oranges(-6) and you are able to give 8 oranges(+8), you would have given excess oranges and would be owed two oranges(+2). Hence the results above.

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The probability of any event A given that event B has already taken place is found using the formula P(A|B) = P(A ∩ B)/P(B). This is known as conditional probability, where P(A ∩ B) is the probability of events A and B, and P(B) is the probability of event B.

In the question, we are given that 70% of kids who visit a doctor have a fever and 21% of kids have a fever and sore throats.

We are asked to find the probability that a kid who goes to the doctor has a sore throat given that he has a fever.

We suppose the event of going to the doctor while having a fever to be B, and going to a doctor while having a sore throat to be A.

We are given that 70% of kids who visit a doctor have a fever, that is, the probability of event B, P(B) = 70% = 0.7.

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We are asked to find the probability that a kid who goes to the doctor has a sore throat given that he has a fever, that is, we are asked to find the conditional probability of event A, when event B has already taken place, that is, P(A|B).

By formula, we know that:

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Thus, the probability that a kid who goes to the doctor has a sore throat given that he has a fever is <u>0.30 or 30%</u>.

Learn more about conditional probability at

brainly.com/question/10739997

#SPJ4

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