Answer:
Required number is 4.
Step-by-step explanation:
Let the required number be a.
Given,
Sum of ten times the integer and seven times it’s square is 152.
= > Ten times of a + seven times of it's square = 152
= > 10( a ) + 7( a )^2 = 152
= > 10a + 7a^2 - 152 = 0
= > 7a^2 + 10a - 152 = 0
= > 7a^2 + ( 38 - 28 )a - 152 = 0
= > 7a^2 + 38a - 28a - 152 = 0
= > a( 7a + 38 ) - 4( 7a + 38 ) = 0
= > ( a - 4 )( 7a + 38 ) = 0
= > a = 4 or - 38 / 7
Hence the required number is 4.
-2+4 is 2/2 is (1,y)
4+0 divided by 2 is 2
coordinate is (1,2)
<u>Answer:</u>
<u>Step-by-step explanation:</u>
We can use the following rule of surds to solve the problem:
,
which means that when multiplying two numbers with the same bases, we can simply add their powers while keeping the base the same.
Applying this rule:
⇒ 
⇒ 
Answer: 68887
Step-by-step explanation: the geometics series is (the previous number in the series) x 3, so 63 x 3 =189 x 3 =567 x 3 = 1701 x 3 = 5103 x 3 =15309 x 3 = 45927 and you add all those numbers up to get 68887
