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2 years ago

Make x the subject of e = bx-dYA'LL PLEASE I CAN'T DO MATHS

Mathematics

2 answers:

tresset_1 [31]2 years ago

7 0

<h3>Answer: x = (e+d)/b</h3>

Explanation:

Your teacher wants you to isolate x.

We first undo the "minus d" by adding d to both sides. Then we divide both sides by b to undo the multiplication. In short, we follow PEMDAS in reverse undoing everything to isolate the variable.

So,

e = bx-d

e+d = bx

bx = e+d

x = (e+d)/b

hjlf2 years ago

4 0

Answer:

x = $\frac{e+d}{b}$

Step-by-step explanation:

Given

e = bx - d ( add d to both sides )

e + d = bx ( isolate x by dividing both sides by b )

$\frac{e+d}{b}$ = x

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2 years ago

A 16-oz bottle of water costs $1.44. What is the cost per ounce?

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3 years ago

What is the area of the square?

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3 years ago

what is the equation, in slope- intercept form, of the line that contains the points (-3,4) and (5,7)

gavmur [86]

Answer:

y = $\frac{3}{8}$ x + $\frac{41}{8}$

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

To calculate the slope use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (- 3, 4) and (x₂, y₂ ) = (5, 7)

m = $\frac{7-4}{5+3}$ = $\frac{3}{8}$ , hence

y = $\frac{3}{8}$ x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

using (5, 7 ), then

7 = $\frac{15}{8}$ + c ⇒ c = 7 - $\frac{15}{8}$ = $\frac{41}{8}$

y = $\frac{3}{8}$ x + $\frac{41}{8}$ ← equation in slope-intercept form

6 0

3 years ago

[30 POINTS] Please help!!!

Len [333]

Answer:

Part 1) $y=1.5x+5$

Part 2) $y=-(2/3)x-(11/3)$

Part 3) $y=0.25x+2.75$

Part 4) $y=-2x+5$

Part 5) $y=0.5x-1$

Part 6) The graph in the attached figure

Step-by-step explanation:

Part 1) we have

$m=3/2=1.5$

$point(-2,2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-2=1.5(x+2)$

$y=1.5x+3+2$

$y=1.5x+5$

Part 2) we know that

If two lines are perpendicular

then

the product of their slopes is equal to minus one

$m1*m2=-1$

the slope of the line 1 is equal to

$m1=1.5$

Find the slope m2

$1.5*m2=-1$

$m2=-2/3$

Find the equation of the line 2

we have

$m2=-2/3$

$point(-7,1)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-1=(-2/3)(x+7)$

$y=-(2/3)x-(14/3)+1$

$y=-(2/3)x-(11/3)$

Part 3) we have

$m=1/4=0.25$

$point(1,3)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-3=0.25(x-1)$

$y=0.25x-0.25+3$

$y=0.25x+2.75$

Part 4) we have

$m=-2$

$b=5$ -----> y-intercept

we know that

The equation of the line into slope intercept form is equal to

$y=mx+b$

substitute the values

$y=-2x+5$

Part 5) we have that

The slope of the line 4 is equal to $-2$

the slope of the line perpendicular to the line 4 is equal to

$-2*m=-1\\m=(1/2)=0.5$

therefore

in this problem we have

$m=0.5$

$point(-2,-2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y+2=0.5(x+2)$

$y=0.5x+1-2$

$y=0.5x-1$

Part 6)

using a graphing tool

see the attached figure

3 0

3 years ago

Make x the subject of e = bx-dYA'LL PLEASE I CAN'T DO MATHS​

Make x the subject of e = bx-dYA'LL PLEASE I CAN'T DO MATHS