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3 years ago

Taylor is making a cookie cake that has a diameter of 13 in. What is the area of a fourth of the cookie cake?

Mathematics

2 answers:

emmasim [6.3K]3 years ago

7 0

Diameter:13 in

r=13/2=6.5 in

Aria of the whole cookie cake:r*r*pi = 6.5*6.5*3.14=132.665 and then you divide it by 4 and you get 33.18

So, the answer is C:33.18

weqwewe [10]3 years ago

5 0

Cookie Cake is in the form of a circle.

Radius of circle = 1/2 * diameter of circle = 1/2*13=13/2=6.5 in

Thus the Area of the circle = $\pi r^2$

= $\pi *6.5^2$

$= 132.73$

Area of a fourth of the Cookie cake $= \frac{1}{4} *132.73 = 33.18 in^2$

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Veronica is choosing between two health clubs after how many months will the total cost for each health club be the same

Assoli18 [71]

Question:

Veronica is choosing between two health clubs. after how many months will the total cost for each health club be the same? yoga studio a: membership: $24.00 monthly fee: 21.50. yoga studio b: membership: $41.00 monthly fee: $17.25

Answer:

It takes 4 years for the total cost of each club to become equal

Step-by-step explanation:

Given:

For yoga studio A:

membership: $24.00

monthly fee: 21.50.

For yoga studio B:

membership: $41.00

monthly fee: $17.25

To Find:

Number of months after which the total cost for each health club be the same = ?

Solution:

Let x be the number of months of membership, and y be equal the total cost.

For Yoga club A

y = 21.50 x + 24

For Yoga club B

y = 17.25 x + 41.00

we know that the prices, y , would be equal, we can set the two equations equal to each other.

21.50 x + 24 =17.25 x+ 41.00

Grouping the like terms,

21.50x - 17.25 x= 41.00 - 24

4.25x=17

x= $\frac{17}{4.25}$

x = 4

6 0

3 years ago

4(3x^2y^4)^3 / (2x^3y^5)^4

tatyana61 [14]

Solving the expressions $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$ we get $\frac{27}{4x^{6}y^{8}}$

Step-by-step explanation:

We need to Solve the expression: $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$

Solving:

$\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$

$=\frac{4(3^3x^6y^{12})}{(2^4x^{12}y^{20})}\\=\frac{4(27x^6y^{12})}{(16x^{12}y^{20})}\\=\frac{108x^6y^{12}}{16x^{12}y^{20}}$

Applying exponent rule: $\frac{x^a}{x^b}=x^{a-b}$

$=\frac{108x^{6-12}y^{12-20}}{16}\\=\frac{27x^{-6}y^{-8}}{4}$

Another exponent rule says: $x^{-a}=\frac{1}{x^a}=$

$=\frac{27}{4x^{6}y^{8}}$

So, solving the expressions $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$ we get $\frac{27}{4x^{6}y^{8}}$

Keywords: Solving Exponents

Learn more about Solving Exponents at:

#learnwithBrainly

8 0

3 years ago

In the equation 0.75 - 5/8s = 44, how do your combine the like terms?

Mnenie [13.5K]

Answer:

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Step-by-step explanation:

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Mkey [24]

Answer:

i got 32031.14

Step-by-step explanation:

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2 years ago

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puteri [66]

Answer:

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3 years ago