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kramer
3 years ago
5

Taylor is making a cookie cake that has a diameter of 13 in. What is the area of a fourth of the cookie cake?

Mathematics
2 answers:
emmasim [6.3K]3 years ago
7 0

Diameter:13 in

r=13/2=6.5 in

Aria of the whole cookie cake:r*r*pi = 6.5*6.5*3.14=132.665 and then you divide it by 4 and you get 33.18

So, the answer is C:33.18

weqwewe [10]3 years ago
5 0

Cookie Cake is in the form of a circle.

Radius of circle = 1/2 * diameter of circle = 1/2*13=13/2=6.5 in

Thus the Area of the circle = \pi r^2

= \pi *6.5^2

= 132.73

Area of a fourth of the Cookie cake = \frac{1}{4} *132.73 = 33.18 in^2

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A standard American Eskimo dog has a mean weight of 30 pounds with a standard deviation of 2 pounds. Assuming the weights of sta
lions [1.4K]

Answer:

Approximately 24–36 pounds

Step-by-step explanation:

Given:

Weight of standard American Eskimo dog has mean= 30 pounds

A standard deviation= 2 pounds

For 99.7% of the dogs according to normal distribution would lie between 3 standard deviations on either side of the mean.

i.e. lower bound= Mean- 3 (standard deviation)

= 30-3(2)

=30-6

=24

Upper bound = Mean +3 (standard deviation)

= 30+3(2)

=30+6

=36

Hence the range of weights : 24-36 pounds

correct answer Approximately 24–36 pounds!

4 0
3 years ago
PLZ HELP ASAP ASAP ASAP I HAVE TO GET THIS ODNE ITS DUE IN 20 MINUTES​
pishuonlain [190]

Answer: C. -25 is the least one, B. 25 is the first one, A. 1/25 is the second, and D. -1/25 is the third. So in a simpler way Least to Greatest is -25, -1/25, 1/25, 25. I hope this helped!

5 0
1 year ago
Read 2 more answers
How many and what type of solutions does the equation have?
Natali [406]
Let's solve the equation 2k^2 = 9 + 3k
First, subtract each side by (9+3k) to get 0 on the right side of the equation
2k^2 = 9 + 3k
2k^2 - (9+3k) = 9+3k - (9+3k)
2k^2 - 9 - 3k = 9 + 3k - 9 - 3k
2k^2 - 3k - 9 = 0

As you see, we got a quadratic equation of general form ax^2 + bx + c, in which a = 2, b= -3, and c = -9.
Δ = b^2 - 4ac
Δ = (-3)^2 - 4 (2)(-9)
Δ<u /> = 9 + 72
Δ<u /> = 81

Δ<u />>0 so the equation got 2 real solutions:
k = (-b + √Δ)/2a = (-(-3) + √<u />81) / 2*2 = (3+9)/4 = 12/4 = 3
AND
k = (-b -√Δ)/2a = (-(-3) - √<u />81)/2*2 = (3-9)/4 = -6/4 = -3/2

So the solutions to 2k^2 = 9+3k are k=3 and k=-3/2

A rational number is either an integer number, or a decimal number that got a definitive number of digits after the decimal point.

3 is an integer number, so it's rational.
-3/2 = -1.5, and -1.5 got a definitive number of digit after the decimal point, so it's rational.

So 2k^2 = 9 + 3k have two rational solutions (Option B).

Hope this Helps! :)
7 0
3 years ago
Read 2 more answers
Please help! Please let me know if you need a better picture.
Dmitriy789 [7]

Answer:

-2

Step-by-step explanation:

First you should write out the entire word equation into one you may recongnize:

7x - 12 = -3x - 32

After this, solve for x:

7x + 3x = 12 - 32

<u>10x</u> = <u>-20</u>

10      10

x = -2

the number is -2

5 0
2 years ago
Evaluate.
lana66690 [7]
53-(64:8)+102=53-8+102=147
4 0
2 years ago
Read 2 more answers
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