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brilliants [131]
3 years ago
12

What is the slope of the following graph?

Mathematics
1 answer:
mel-nik [20]3 years ago
6 0
I dont know if this helps since no one else is answering I’d like to help
To find slope.. the M in the slope formula of y=Mx+b represents slope

So as long as you know what point on the graph represents what then it should be easy

In most cases.. finding slope is where the line meets on the x axis
You might be interested in
By what number should 1 1/2 be divided to get 2/3 ? *
andrew-mc [135]

Answer:

1

Step-by-step explanation:

1) The equation is 1 1/2 ÷ x = 2/3

2) You can multiply 2/3 with 1 1/2 to get your answer

3) 2/3 × 1 1/2 = 1

Hope this helps!

4 0
3 years ago
What is the sum of 6dm, 40mm, 2m and 10cm in meters?
sveticcg [70]

Answer:

<h2><u><em>2.74 m</em></u></h2>

Step-by-step explanation:

<u><em>convert to meters</em></u>

6 dm = 0.6 m

40 mm = 0.04 m

2 m = 2 m

10 cm = 0.1 m

sum

0.6 + 0.04 + 2 + 0.1 =

2.74 m

7 0
2 years ago
Read 2 more answers
Factor completely. n^2 + 7n - 44
4vir4ik [10]
(n+11)(n-4) is your answer
4 0
3 years ago
Read 2 more answers
Help me with the work please if you can
timurjin [86]

Answer:

1/3

Step-by-step explanation:

48+32+16=96

numerator : 32

denominator : 96

32/96=1/3

6 0
3 years ago
A manufacturing plant earned $80 per man-hour of labor when it opened. Each year, the plant earns an additional 5% per man-hour.
baherus [9]

A function that gives the amount that the plant earns per man-hour t years after it opens is \mathrm{A}(\mathrm{t})=80 \times 1.05^{\mathrm{t}}

<h3><u>Solution:</u></h3>

Given that  

A manufacturing plant earned $80 per man-hour of labor when it opened.

Each year, the plant earns an additional 5% per man-hour.

Need to write a function that gives the amount A(t) that the plant earns per man-hour t years after it opens.  

Amount earned by plant when it is opened = $80 per man-hour

As it is given that each year, the plants earns an additional of 5% per man hour

So Amount earned by plant after one year = $80 + 5% of $80 = 80 ( 1 + 0.05) = (80 x 1.05)

Amount earned by plant after two years is given as:

=(80 \times 1.05)+5 \% \text { of }(80 \times 1.05)=(80 \times 1.05)(1.05)=80 \times 1.052

Similarly Amount earned by plant after three years =80 \times 1.05^{t}

\begin{array}{l}{\Rightarrow \text { Amount earned by plant after } t \text { years }=80 \times 1.05^{t}} \\\\ {\Rightarrow \text { Required function } \mathrm{A}(t)=80 \times 1.05^{t}}\end{array}

Hence a function that gives the amount that the plant earns per man-hour t years after it opens is \mathrm{A}(t)=80 \times 1.05^{t}

5 0
3 years ago
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