Answer:
let's find the gradient first. (m)
Step-by-step explanation:
(10,3) (6,31)
y²-y¹/x²-x¹
31-3/6-3
28/3
(m) =28/3
y-y¹=m(x-x¹)
let's take y¹=3, x¹=10 and m= 28/3
y-3=28/3(x -10)
y-3=(28/3)x -128/3
taking LCM=3
3y-9=28x-128
3y=28x -128+9
3y=28x-119
Soo your equation is:
3y=28x-119
Answer:
Step-by-step explanation:
Cross multiplication can be used but not in the beginning. First x should be isolated.
Now subtract 
from both sides
In this stage, cross multiplication can be used.
Answer:
AAS method can be used to prove that the two triangles are congruent.
Step-by-step explanation:
According to the question for the two triangles one pair of opposite angles are equal. One another pair of angles are equal for the two and one pair of sides are also equal of the two.
Hence, the two given triangles are congruent by AAS rule.
Hence, AAS method can be used to prove that the two triangles are congruent.
The slope is (8-2)/(0-2)=-3
the y intercept is 8
the equation is y=-3x+8
the area to the left is shaded, and the line is solid, so y
-3x+8
The perimeter of a triangle is the sum of all its side lengths
11.3 + 14.7 + x < 44
Combine like terms
26 + x < 44
Subtract 26 from both sides.
x < 18
