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Mars2501 [29]
3 years ago
9

Please help parts b and c

Mathematics
1 answer:
zimovet [89]3 years ago
5 0

Answer:

a = 2

b = 4

c = 8

Step-by-step explanation:

Remember the relationship:

(a^{x})^{y} = a^{x*y}

First, in "a" we have:

a) 8^{1/3}  = \sqrt[3]{8}  = 2

then in the next ones, we can use the result that we obtained in the part a:

b) 8^{2/3} = (8^{1/3})^2 = (2)^2 = 4

Now we can do exactly the same in c:

c) where first we need to know that:

2*2*2*2 = 4*4 = 16

then:

2^4 = 16

then:

\sqrt[4]{16} = 16^{1/4} =  2

Now let's solve the problem:

16^{3/4} = (16^{1/4})^3 = (2)^3 = 2*2*2 = 8

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