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Neko [114]
3 years ago
5

I need to see where to put the points on the graph​

Mathematics
2 answers:
Mumz [18]3 years ago
7 0

Answer:

Step-by-step explanation:

ok so

42≤0.45x+0.60y

x=pounds of finnishing nails

y=pounds common nails

when x+y≥30

now lets solve for y

y=-x+30

lets plug this in to the formula

42≤0.45x+0.6(−x+30)

x≤−160

nowing this lets plug in for x

x+y≥30

-160+y≥30

y≥190

NARA [144]3 years ago
7 0

Answer:

Step-by-step explanation:

42≤0.45x+0.60y

x=pounds of finnishing nails

y=pounds common nails

when x+y≥30

now lets solve for y

y=-x+30

lets plug this in to the formula

42≤0.45x+0.6(−x+30)

x≤−160

nowing this lets plug in for x

x+y≥30

-160+y≥30

y≥190

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2b+y is this an equation?
lutik1710 [3]

Answer:

No because equations have equal signs

Step-by-step explanation:

This is an expression

3 0
2 years ago
Susan made 4 uniform annual deposits of $1800 in a savings account that earned an interest rate of 2% per year. Her last deposit
Norma-Jean [14]

Answer:

"$ 2,880" is the right answer.

Step-by-step explanation:

The given values are:

Annual deposit,

PV = $1,800

Interest rate,

r = 2%

or,

  = 0.02

As we know,

⇒  FV=PV\times (1+r)n

On substituting the values, we get

⇒         =1,800\times  (1 + 0.02) 4 + 7 + 13

⇒         =1,800\times (1.02)24

⇒         =1,800\times 1.6

⇒         = 2,880 ($)

5 0
3 years ago
How would i solve y=x+z/a-x and solve for x
Alborosie

Answer:

<h3>ya-z/1+y</h3>

Step-by-step explanation:

Making x the subject of the formula;

y=x+z/a-x

Cross multiply

y(a-x) = x+z

ya - yx = x+z

Collect like terms

x+yx = ya - z

x(1+y) = ya - z

x = ya-z/1+y

Hence the value of x is ya-z/1+y

4 0
3 years ago
Heeeeelp pleaseeeee <br> A=1/2ap solve for p
dem82 [27]
2*A=2*1/2ap -- 2A/a=pa/a -- answer is 2A/a=P or P=2A/a
6 0
4 years ago
In a class of 18 students, 5 are math majors. A group of four students is chosen at random. (Round your answers to four decimal
ss7ja [257]

Answer:

(a) 0.2721

(b) 0.7279

(c) 0.2415

Step-by-step explanation:

(a) If we choose only one student, the probability of being a math major is \frac{5}{18} (because there are 5 math majors in a class of 18 students). So, the probability of not being a math major is \frac{18}{18} - \frac{5}{18} = \frac{13}{18} (we subtract the math majors of the total of students).

But there are 4 students in the group and we need them all to be not math majors. The probability for each one of not being a math major is \frac{13}{18} and we have to multiply them because it happens all at the same time.

P (no math majors in the group) = \frac{13}{18} *\frac{13}{18}*\frac{13}{18}*\frac{13}{18} = (\frac{13}{18}) ^4 = 0.2721

(b) If the group has at least one math major, it has one, two, three or four. That's the complement (exactly the opposite) of having no math majors in the group. That means 1 = P (at least one math major) + P (no math major). We calculated this last probability in (a).

So, P (at least one math major) = 1 - P(no math major) = 1 - 0.2721 = 0.7279  

(c) In the group of 4, we need exactly 2 math majors and 2 not math majors. As we saw in (a), the probability of having a math major in the group is 5/18 and having a not math major is \frac{13}{18}. We need two of both, that's \frac{5}{18}*\frac{5}{18}*\frac{13}{18}*\frac{13}{18}. But we also need to multiply this by the combinations of getting 2 of 4, that is given by the binomial coefficient \binom{4}{2}.

So, P (exactly 2 math majors) = \binom{4}{2}*(\frac{5}{18} )^2*(\frac{13}{18})^2 = \frac{4!}{2!2!}*\frac{25}{324}*\frac{169}{324} = 0.2415

7 0
4 years ago
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