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melisa1 [442]
3 years ago
6

Suppose f(x) = 3x2 – 2x: Find f(-4). А B -40 ОО C 56plz helpp​

Mathematics
1 answer:
amid [387]3 years ago
7 0

Answer:

f(-4) = 56

Step-by-step explanation:

f(x) = 3x² - 2x

To find f(-4), substitute -4 for all the values of x in f(x).

f(-4) = 3(-4)² - 2(-4)

Square -4.

f(-4) = 3(16) - 2(-4)

Multiply 3 and 16.

f(-4) = 48 - 2(-4)

Multiply -2 and -4.

48 + 8

Add.

56

You had the right idea! :)

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∠1 and ∠2 are complementary. If m∠1 = 4m∠2, find m∠1
77julia77 [94]

Answer:

∠1 = 72°

Step-by-step explanation:

Complementary angles sum to 90°, thus

∠1 + ∠2 = 90, substitute ∠1 = 4∠2 , thus

4∠2 + ∠2 = 90

5∠2 = 90 ( divide both sides by 5 )

∠2 = 18°

Hence ∠1 = 90 - 18 = 72°

8 0
2 years ago
How do I write the sum of 6x and 2x is at least 39 ?
tatiyna
<h2>Put x = \dfrac{39}{8} I write the sum of 6x and 2x is at least 39 .</h2>

Step-by-step explanation:

We have,,

6x and 2x

To find, the value of x = ?

According to question,

The sum of 6x and 2x is at least 39

∴ 6x + 2x = 39

⇒ 8x = 39

⇒  x = \dfrac{39}{8}

∴ The value of x = \dfrac{39}{8}

Thus, put x = \dfrac{39}{8} I write the sum of 6x and 2x is at least 39 .

5 0
3 years ago
A rental car agency charges a flat fee of $139.00 plus $30.00 per day to rent a certain car. Another agency charges a fee of $13
Sveta_85 [38]
139 + 30d = 13 + 51d
139 - 13 = 51d - 30d
126 = 21d
126/21 = d
6 = d

now lets check..
139 + 30d = 139 + 30(6) = 319
13 + 51d = 13 + 51(6) = 319

so on day 6, they will both cost $ 319

5 0
3 years ago
A private and a public university are located in the same city. For the private university, 1038 alumni were surveyed and 647 sa
Snezhnost [94]

Answer:

The difference in the sample proportions is not statistically significant at 0.05 significance level.

Step-by-step explanation:

Significance level is missing, it is  α=0.05

Let p(public) be the proportion of alumni of the public university who attended at least one class reunion  

p(private) be the proportion of alumni of the private university who attended at least one class reunion  

Hypotheses are:

H_{0}: p(public) = p(private)

H_{a}: p(public) ≠ p(private)

The formula for the test statistic is given as:

z=\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

  • p1 is the sample proportion of  public university students who attended at least one class reunion  (\frac{808}{1311}=0.616)
  • p2 is the sample proportion of private university students who attended at least one class reunion  (\frac{647}{1038}=0.623)
  • p is the pool proportion of p1 and p2 (\frac{808+647}{1311+1038}=0.619)
  • n1 is the sample size of the alumni from public university (1311)
  • n2 is the sample size of the students from private university (1038)

Then z=\frac{0.616-0.623}{\sqrt{{0.619*0.381*(\frac{1}{1311} +\frac{1}{1038}) }}} =-0.207

Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.  

6 0
3 years ago
Please please help me I will give brainileist
Temka [501]

Answer:

26

Step-by-step explanation:

Average = all the numbers added together then divided by the amount of numbers in the equation

21+24+25+25+26+26+26+26+27+29= 255

Since there are ten numbers in this equation, divide the sum by 10

25.5

round up

26

7 0
2 years ago
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