Answer:
Explanation:
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Answer:
When an instruction is sent to the CPU in a binary pattern, how does the CPU know what instruction the pattern means
Explanation:
When the CPU executes the instructions, it interprets the opcode part of the instruction into individual microprograms, containing their microcode equivalents. Just so you know, a full assembly instruction consists of an opcode and any applicable data that goes with it, if required (register names, memory addresses).
The assembly instructions are assembled (turned into their binary equivalent 0s and 1s, or from now on, logic signals). These logic signals are in-turn interpreted by the CPU, and turned into more low-level logic signals which direct the flow of the CPU to execute the particular instruction.
Answer:
words.hasNext()
Explanation:
Given the code snippet below:
- while (inputFile.hasNextLine()) {
- String word = "";
- String line = inputFile.nextLine();
- Scanner words = new Scanner(line);
- while (words.hasNext()) {
- word = words.next();
- }
- System.out.println(word); }
- }
We have a inputFile Scanner object that can read data from a text file and we presume the inputFile has read several rows of data from the text file. So long as there is another line of input data available, the outer while loop will keep running. In each outer loop, one line of data will be read and assign to line variable (Line 3). Next, there is another Scanner object, words, which will take the current line of data as input. To get the last word of that line, we can use hasNext() method. This method will always return true if there is another tokens in its input. So the inner while loop will keep running so long as there is a token in current line of data and assign the current token to word variable. The word will hold the last token of current line of data upon exit from the inner loop. Then we can print the output (Line 8) which is the last word of the current line of data.
