Answer:
a) the average CPI for machine M1 = 1.6
the average CPI for machine M2 = 2.5
b) M1 implementation is faster.
c) the clock cycles required for both processors.52.6*10^6.
Explanation:
(a)
The average CPI for M1 = 0.6 x 1 + 0.3 x 2 + 0.1 x 4
= 1.6
The average CPI for M2 = 0.6 x 2 + 0.3 x 3 + 0.1 x 4
= 2.5
(b)
The average MIPS rate is calculated as: Clock Rate/ averageCPI x 10^6
Given 80MHz = 80 * 10^6
The average MIPS ratings for M1 = 80 x 10^6 / 1.6 x 10^6
= 50
Given 100MHz = 100 * 10^6
The average MIPS ratings for M2 = 100 x 10^6 / 2.5 x 10^6
= 40
c)
Machine M2 has a smaller MIPS rating
Changing instruction set A from 2 to 1
The CPI will be increased to 1.9 (1*.6+3*.3+4*.1)
and hence MIPS Rating will now be (100/1.9)*10^6 = 52.6*10^6.
Answer:
(9F7, 9F8, 9F9, 9FA, 9FB, 9FC, 9FD, 9FE, 9FF, A00, A01, A02, A03)
Explanation:
This means that we must find all hexadecimal values from 2551 to 2563, or 9F7 to A03. You can convert from decimal to hexadecimal for each one, or just count.
Answer:
The answer is letter C. The letter C is the true statement.
Explanation:
The true statement is The point-of-sale terminal cannot connect directly to the Internet.
Answer: D.
Data about user preferences and activity is captured and stored under a cookie on a company’s Web server.
Explanation: The most common and best-known technology for user tracking is the use of cookies. Other known online website tracking tools are tracking pixels (or pixel tags), web beacons (or ultrasound beacons), and browser fingerprinting (or digital fingerprinting), amongst others.
a cookie will contain a string of text that contains information about the browser. To work, a cookie does not need to know where you are from, it only needs to remember your browser. Some Web sites do use cookies to store more personal information about you.
Answer:
see below
Explanation:
The program of interest is the function "findMode[x, n]" in the attached. It is written the Wolfram Language of Mathematica.
The basic idea is that the data in the array is sorted. The sorted array is partitioned into sets of identical elements, and the number in each of those sets is counted. The maximum of those counts is the mode. The location of the maximum count corresponds to the location of the set having that count. We use that location information to pull out the mode value(s).
If there is more than one mode, all are reported.
__
An example data array is provided, along with the program output.
