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ss7ja [257]
3 years ago
10

The product of a number and 3 is 87 what is the number

Mathematics
2 answers:
IrinaK [193]3 years ago
8 0
The awnser would be 29
n200080 [17]3 years ago
3 0

Answer:

Hey buddy, here is your answer. Hope it helps yo.

Step-by-step explanation:

Let the unknown number be x,

x * 3=87. To find out the x we need to divide 87 by 3. That gives you 29. So the unknown number is 29. 29*3=87.

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Alebgra!!
Vikentia [17]

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I think it's 18

Step-by-step explanation:

P=2(l+w)=2(7+2)=18

it's been awhile I believe this is it

4 0
2 years ago
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Heights of adult males are known to have a normal distribution. a researcher claims to have randomly selected adult males and me
8090 [49]

Answer:

The sum of the probabilities is greater than 100%; and the distribution is too uniform to be a normal distribution.

Step-by-step explanation:

The sum of the probabilities of a distribution should be 100%.  When you add the probabilities of this distribution together, you have

22+24+21+26+28 = 46+21+26+28 = 67+26+28 = 93+28 = 121

This is more than 100%, which is a flaw with the results.

A normal distribution is a bell-shaped distribution.  Graphing the probabilities for this distribution, we would have a bar up to 22; a bar to 24; a bar to 21; a bar to 26; and bar to 28.

The bars would not create a bell-shaped curve; thus this is not a normal distribution.

3 0
3 years ago
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Find the volume of the prism.
Alex_Xolod [135]

Answer:

c. 120 units^3

Step-by-step explanation:

L x W x H = <em>V</em>

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6 0
3 years ago
Write a definite integral that represents the area of the region. (Do not evaluate the integral.)
joja [24]

Answer:

\int_{-1}^{1}7(x^{3}-x)\:dx

Step-by-step explanation:

1)  The other curve is y=0 then the common points of both curves are x-intercepts, the roots of y=7(x^{3}-x)

y=7(x^{3}-x)\Rightarrow 7(x^3-x)=0 \Rightarrow 7(x^{3}-x)=7x(x-1)(x-1)\Rightarrow \\S=\left ( 0,0 \right ),\left ( -1,0 \right ),\left ( 1,0 \right )

2). Then those intersection points are the upper and the lower limits. Plugging in to this formula for they belong to the interval [-1,1]:

\int_{a}^{b}|f(x)-g(x)dx

\int_{a}^{b}|f(x)-g(x)dx \Rightarrow \int_{-1}^{1}|7(x^{3}-x)-0|dx \Rightarrow \int_{-1}^{1}7(x^{3}-x)\:dx

 

8 0
3 years ago
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