Question

Find the equation of a line parallel to y'= -8x+6.

Answer 1

Answer:

The equation must include -8 as the slope

Step-by-step explanation:

Hi there!

Two key points to keep in mind:

1. Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when x is 0).
2. Parallel lines always have equal slopes

Given the equation y=-8x+6, we can identify that -8 is in the place of m in y=mx+b, making it the slope.

For a line to be parallel to y=-8x+6, it would have to have a slope of -8 as well. This is the only quality a line needs to be parallel to this given line.

I hope this helps!