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blsea [12.9K]
3 years ago
5

Solve the equation 8 - (x - 2) = 2x + (10 – 3x)

Mathematics
2 answers:
Alinara [238K]3 years ago
8 0

Answer:

a) No solution

Step-by-step explanation:

This has no solution because x is eliminated from the equation when simplifying, giving us a nonsensical answer:

8 - (x - 2) = 2x + (10 - 3x)

8 - 2 - x = 2x - 3x + 10

6 - x = - x + 10

6 = 10

algol133 years ago
5 0
A) no solution no solution
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Find the value of Y in the figure above .
Blizzard [7]

9514 1404 393

Answer:

  • x = 37
  • y = 22

Step-by-step explanation:

Consecutive interior angles are supplementary.

  (x -20)° +(4x +15)° = 180°

  5x = 185 . . . . . . . . . . . . . . divide by °, add 5

  x = 37 . . . . . . . . . . . . divide by 5

__

  74° +(5y -4)° = 180°

  5y = 110 . . . . . . . . . . . divide by °, subtract 70

  y = 22 . . . . . . . . . . divide by 5

3 0
4 years ago
2(3x-12)=6(x-2)<br><br> PLEASE HELP!!!
Zarrin [17]
ANSWER: There are no solutions
6 0
3 years ago
6.87 + 5.38 equals what as a whole number or a decimal
Helga [31]
Decimal answer...I got 12.25 when added together.
7 0
3 years ago
Find the area of quadrilateral ABCD whose vertices are A(1,1) B(7,-3) C(12,2) D(7,21)
sasho [114]

Answer:

The area of quadrilateral ABCD is 139 unit^2.

Step-by-step explanation:

Given:

Quadrilateral ABCD whose vertices are A(1,1) B(7,-3) C(12,2) D(7,21).

Now, to find the area.

The coordinates of the quadrilateral are A(1,1), B(7,-3), C(12,2), D(7,21).

So, to find the area we need to bisect the quadrilateral ABCD and get the triangles ABC and ADC and then calculate their areas:

In Δ ABC:

A(x_1,y_1)=(1,1)\:,\:B(x_2,y_2)=(7,-3)\:and\:C(x_3,y_3)=(12,2)

Now, to get the area of triangle ABC:

Area\,of\,triangle\,=\,\frac{1}{2}\left|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)\right|

Area\,of\,triangle\,=\,\frac{1}{2}\left|1(-3-2)+(7)(2-1)+12(1--3)\right|

Area\,of\,triangle\,=\,\frac{1}{2}\left|1(-5)+(7)(1)+12(4)\right|

On solving we get:

Area\,of\,triangle\,=25.

In Δ ADC:

A(x_1,y_1)=(1,1)\:,\:D(x_2,y_2)=(7,21)\:and\:C(x_3,y_3)=(12,2)

Now, to get the area of triangle ADC:

Area\,of\,triangle\,=\,\frac{1}{2}\left|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)\right|

Area\,of\,triangle\,=\,\frac{1}{2}\left|1(21-2)+(7)(2-1)+12(1-21)\right|

On solving it by same process as above we get:

Area\,of\,triangle\,=114

Now, to get the area of the quadrilateral we add the areas of the triangles ABC and ADC:

25+114\\=25+114\\=139\ unit^2

Therefore, area of quadrilateral ABCD is 139 unit^2.

4 0
3 years ago
10+6 has the same sum as 7+
lisabon 2012 [21]
10+6=16
7+9=16 
Therefore, the mystery number is 9.
3 0
3 years ago
Read 2 more answers
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