Help pleaseee.... #5

Anettt [7]

Answer:

it would be A. it would be A because on the x coordinate would be placed like (x, y) 4 is negative and 6 is positive, hence (-4, 6)

Step-by-step explanation:

<em>can i have brainliest?</em>

5 0

3 years ago

Write the equation in standard form. Identity the center and radius.<br> x² + y2 + 8x-4y-7=0

lorasvet [3.4K]

Answer:

equation;

$(x + 4) {}^{2} + (y - 2) {}^{2} = 27$

Center (-4,2)

Radius is

$3 \sqrt{3}$

Step-by-step explanation:

Since the x^2 and y^2 have the same coeffiecent this will be a circle in a form of

$(x - h) {}^{2} + (y - k) {}^{2} = {r}^{2}$

Where (h,k) is center

r is the radius

So first we group like Terms together

${x}^{2} + 8x + {y}^{2} - 4y - 7 = 0$

Add 7 to both sides

${x}^{2} + 8x + {y}^{2} - 4y = 7$

$( {x}^{2} + 8x) +( {y}^{2} - 4y) = 7$

Since the orginal form of the equation of the circle has a perfect square we need to complete the square for each problem

$(\frac{8}{2} ) {}^{2} = 16$

and

$( - \frac{4}{2} ) {}^{2} = 4$

so we have

${x}^{2} + 8x + 16 + {y}^{2} - 4y + 4y = 7 + 16 + 4$

${x}^{2} + 8x + 16 + {y}^{2} - 4y + 4y = 27$

$(x + 4) {}^{2} + (y - 2) {}^{2} = 27$

To find our center, h is -4 and k is 2

so the center is (-4,2)

The radius is

$\sqrt{27} = 3 \sqrt{3}$

So the radius is 3 times sqr root of 3.

8 0

2 years ago

Mrs. Smith gave two classes the same quiz. She randomly selected 5 students from each class to compare the classes. The scores o

Tasya [4]

The mean and range for class A are 84.4 and 20 while the mean and range for class B are 83.6 and 8. Class B is more consistant then class A.

<h3>How to calculate the mean?</h3>

We can see from the data that the consistency of class B is more becuase the repeatation of the same score is more in class B then class A and the range of class B is also less then the class A.

It should be noted that mean simply means average. It's the addition of the numbers divided by the total numbers.

In this case, the computation will be:

Class A: Mean = 422/5= 84.4.

Range: 94-74 = 20

Class B: Mean = 418/5 = 83.6.

Range= 88-80 = 8

Learn more about mean on:

brainly.com/question/1136789

#SPJ1

4 0

1 year ago

15 × (-3) × n = 908989

Juliette [100K]

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5 0

3 years ago

8x+3y= 28 and 7x-3y=2<br>solve for x and y simontaniasly using elimination

EleoNora [17]

Answer:

x=2, y=4

Step-by-step explanation:

When using elimination, the objective is to elimate one variable. In this case, we see that "y" can easily be eliminated by adding the two equations together since you will get 3y + (-3y) which will eliminate y because the value would become 0, letting us solve for x.

$\left \{ {{8x+3y=28} \atop {7x-3y=2}} \right. +\\$

Then we get

$15x =30$ , because the y's will eliminated, and 8x+7x is 15x, and 28+2 is 30.

Then divide by 15 on both sides and you get x=2

If x=2, then we can substitute that value into any of the previous given equations and find the value of y.

8×2 +3y = 28

16+3y=28

3y=12

y=4

So the answer to your system of equations would be x=2, and y=4

You can substitute the answers we found to see that they satisfy the equation.

Hope this helped.

6 0

3 years ago