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nevsk [136]
2 years ago
13

−2t−5<9 Hiiiiiiii Huuuu

Mathematics
2 answers:
creativ13 [48]2 years ago
5 0

HELLO

now you can give the other person brainiest

Brilliant_brown [7]2 years ago
4 0

Answer:

t > -7

Step-by-step explanation:

To solve for t, first add 5 to both sides:

-2t - 5 < 9

-2t < 14

Divide each side by -2, and flip the inequality because we are dividing by a negative number:

-2t < 14

t > -7

So, the solution is t > -7

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an elderly patient goes to a general doctor every 4 weeks and goes to a chiroprator every 6 weeks . if he went to both the gener
Fed [463]

Answer:

Step-by-step explanation:

He will actually need to wait for 12 weeks. And that is because if you look at the multiples of 6 and 4 and you'll notice that 12 is the lowest common multiple between them. So you start counting from 6 and 4 at the same time until you notice the LCM of these two numbers then on which ever you number you settle on is how long he will need to wait.

7 0
2 years ago
What is the value of the underlined digit of 2 in 0.812
Varvara68 [4.7K]
Value of 2 in 0.812 = 0.002

Answer:  0.002
6 0
3 years ago
Solve the equation for x in simplest form
spayn [35]

Answer:

A x=1/4

Step-by-step explanation:

2/3x = 1/6

Divide by 2/3

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4 0
3 years ago
The length of a rectangle is increasing at a rate of 6 cm/s and its width is increasing at a rate of 5 cm/s. When
atroni [7]

Answer:

The area of the rectangle is increasing at a rate of 84 square centimeters per second.

Step-by-step explanation:

The area for a rectangle is given by the formula:

A=w\ell

Where <em>w</em> is the width and <em>l</em> is the length.

We are given that the length of the rectangle is increasing at a rate of 6 cm/s and that the width is increasing at a rate of 5 cm/s. In other words, dl/dt = 6 and dw/dt = 5.

First, differentiate the equation with respect to <em>t</em>, where <em>w</em> and <em>l</em> are both functions of <em>t: </em>

\displaystyle \frac{dA}{dt}=\frac{d}{dt}\left[w\ell]

By the Product Rule:

\displaystyle \frac{dA}{dt}=\frac{dw}{dt}\ell +\frac{d\ell}{dt}w

Since we know that dl/dt = 6 and that dw/dt = 5:

\displaystyle \frac{dA}{dt}=5\ell + 6w

We want to find the rate at which the area is increasing when the length is 12 cm and the width is 4 cm. Substitute:

\displaystyle \frac{dA}{dt}=5(12)+6(4)=84\text{ cm}^2\text{/s}

The area of the rectangle is increasing at a rate of 84 square centimeters per second.

8 0
3 years ago
Hey! please help i’ll give brainliest
vesna_86 [32]

Answer:

verb tense refers to when the action and a sentence takes place - whether it happened in the past, is happening in the present, or what is happening in the future.

4 0
2 years ago
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