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Lynna [10]
3 years ago
14

Is the histogram uniform, symmetric, or skewed?

Mathematics
1 answer:
sergeinik [125]3 years ago
8 0

A histogram is a graphical representation of data. A histogram is uniform when it forms almost a straight, horizontal line. It is symmetric when it forms a bell shape, equal parts to both sides. It is skewed when most of the data falls to the left or right.

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F(x) = x2 + 1<br> g(x) = 5-x<br> (f+g)(x) =<br> O x2 + x-4<br> x²+x+4<br> O x2-x+6<br> O x2 + x + 6
charle [14.2K]

Answer:

\boxed{(f + g)(x) = {x}^{2} - x + 6}

Given:

f(x) =  {x}^{2}  + 1 \\  \\ g(x) = 5 - x

To Find:

(f + g)(x) = f(x) + g(x)

Step-by-step explanation:

=  > f(x) + g(x) =  ({x}^{2}  + 1) + (5 - x) \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = {x}^{2}  + 1 + 5 - x\\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = {x}^{2}  + 6 - x\\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = {x}^{2} - x + 6

5 0
3 years ago
24 x 12 1/2 x 12 3/4 what is the volume of the fish tank
hjlf

Answer:

The volume is 3825 cubic units

Step-by-step explanation:

To find the volume of the fish tank multiply out the dimensions.

We were given the dimensions as:

24 \times 12 \frac{1}{2}  \times 12 \frac{3}{4}

Change the numbers to improper fractions

24 \times  \frac{25}{2}  \times \frac{51}{4}

We cancel out to get

3 \times 25 \times 51

3825

5 0
3 years ago
The area of the shaded segment is 100cm^2. Calculate the value of r.
Reil [10]
Hello, 

The formula for finding the area of a circular region is: A=  \frac{ \alpha *r^{2} }{2}

then:
A_{1} = \frac{80*r^{2} }{2}

With the two radius it is formed an isosceles triangle, so, we must obtain its area, but first we obtain the height and the base.

cos(40)= \frac{h}{r}  \\  \\ h= r*cos(40)\\ \\ \\ sen(40)= \frac{b}{r} \\ \\ b=r*sen(40)

Now we can find its area:
A_{2}=2* \frac{b*h}{2}  \\  \\ A_{2}= [r*sen(40)][r*cos(40)]\\  \\A_{2}= r^{2}*sen(40)*cos(40)

The subtraction of the two areas is 100cm^2, then:

A_{1}-A_{2}=100cm^{2} \\ (40*r^{2})-(r^{2}*sen(40)*cos(40) )=100cm^{2} \\ 39.51r^{2}=100cm^{2} \\ r^{2}=2.53cm^{2} \\ r=1.59cm

Answer: r= 1.59cm
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3 years ago
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7-^3<br> Simplify this expression. Use 7 as the base.
katen-ka-za [31]
Hopefully this photo helps

7 0
3 years ago
HEY CAN ANYONE PLS ANSWER DIS MATH QUESTION!!!
kupik [55]

Answer: C

Step-by-step explanation:

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3 years ago
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