<u>Solution:</u> 48cm/s^2
<u>Working:</u>
A = s^2
Derivate s^2 (as it is area formula) which gives
dA/dt = 2s dL/dt
dL/dt = 6cm/s
Hence,
2(6) = 12
Side: 4cm
Hence,
dA/dt = (4)(12) = 48cm/s^2
<em>Feel free to mark this as brainliest :D</em>
The line from the point to its reflection should be perpendicular.If we imagine a line from (5,7) to (2,2), it would have a slope of (2-7)/(2-5) = 5/3.
For that line to be perpendicular to y=-2/5x+6, their slopes should be each other's negative reciprocals.
-2/5 negative reciprocal is 5/2, which is not equal to our calculated 5/3, so (2,2) cannot be the reflected point. Evan was wrong.
Q1-74: AB have slope 6/5, C has -5/6, D 6/5, E -5/6 again.
The answer is <span>y=0.5x+3
</span><span>There are 3 inches of snow on the ground: y = 3
</span><span>When it begins to snow 0.5 inches per hour: y = 0.5x
</span>There are 3 inches of snow on the ground when it begins to snow 0.5 inches per hour: y = 0.5x + 3<span>
</span>
First Factor.
Find inverse by solving for 'x'
