Answer:
In the explanation
Step-by-step explanation:
a) We need to write down the sample space for two coin flips.
X={HH,HT,TH,TT}
P(HH)=0.25 X=2
P(HT)=0.25 X=1
P(TH)=0.25 X=1
P(TT)=0.25 X=0
Then
X=0, P(0)=0.25
X=1, P(1)=0.50
X=2, P(2)=0.25
b) If we filp the coin 4 times we have
4 H + 0 T X=4 P(X)=1/16=0.0625
3 H + 1 T X=3 P(X)=4/16=0.250
2 H + 2 T X=2 P(X)=6/16=0.375
1 H + 3 T X=1 P(X)=4/16=0.250
0 H + 4 T X=0 P(X)=1/16=0.0625
c) If we flip the coin 10 times
10 H + 0 T X=10 P(X)=1/1024=0.001
9 H + 1 T X=9 P(X)=10/1024=0.0098
8 H + 2 T X=8 P(X)=45/1024=0.0439
7 H + 3 T X=7 P(X)=120/1024=0.1172
6 H + 4 T X=6 P(X)=210/1024=0.2051
5 H + 5 T X=5 P(X)=252/1024=0.2461
4 H + 6 T X=4 P(X)=210/1024=0.2051
3 H + 7 T X=3 P(X)=120/1024=0.1172
2 H + 8 T X=2 P(X)=45/1024=0.0439
1 H + 9 T X=1 P(X)=10/1024=0.0098
0 H + 10 T X=0 P(X)=1/1024=0.001
