Whole numbers greater than 6 but less than 16

Lesechka [4]

Step-by-step explanation:

Hi there!!! 

The answer is option A. 

reason look in picture. 

if you want to solve it just cross multiply it,

 $60x = 240000 \times 100$ 

or,

 $x = 24000000 \div 60$ 

and the answer would be 400000.

Hope it helps...

5 0

4 years ago

Suppose F⃗ (x,y)=(x+3)i⃗ +(6y+3)j⃗ . Use the fundamental theorem of line integrals to calculate the following.

Scorpion4ik [409]

In order to use the fundamental theorem of line integrals, you need to find a scalar potential function - that is, a scalar function f(x, y) for which

grad f(x, y) = F(x, y)

This amounts to solving for f such that

∂f/dx = x + 3

∂f/∂y = 6y + 3

Integrating both sides of the first equation with respect to x gives

f = 1/2 x ^2 + 3x + g(y)

Differentiating with respect to y gives

∂f/∂y = dg/dy = 6y + 3

Solving for g gives

g = ∫ (6y + 3) dy = 3y ^2 + 3y + C

and hence

f(x, y) = 1/2 x ^2 + 3x + 3y ^2 + 3y + C

(a) By the fundamental theorem, the integral of F along any path starting at the point P (1, 0) and ending at Q (3, 3) is

∫ F(x, y) • dr = f (3, 3) - f (1, 0) = 99/2 - 7/2 = 46

(b) Now we're talking about a closed path, so the integral is simply 0. We can verify this by checking the integral over the origin-containing paths:

• From the origin to P :

∫ F(x, y) • dr = f (1, 0) - f (0, 0) = 7/2 - 0 = 7/2

• From Q back to the origin:

∫ F(x, y) • dr = f (0, 0) - f (3, 3) = 0 - 99/2 = -99/2

Then the total integral is 7/2 + 46 - 99/2 = 0, as expected.

6 0

3 years ago

PLEASE HELP WHAT IS THE ANSWER!

g100num [7]

Answer:

B

Step-by-step explanation:

5 0

3 years ago

a dime is dropped from a building at 1.024 ft . if the equation for height as a function of time is h(t)=-16t^2+ initial height

babunello [35]

Answer:

The dime hits the ground after 8 sec.

Step-by-step explanation:

Set h(t) = -16t^2 + h(0) equal to 0: -16t^2 + 1,024 ft = 0, or:

16t^2 = 1,024 ft, or:

t^2 = 64 ft^2

Then t = +8 sec

The dime hits the ground after 8 sec.

7 0

3 years ago

On Monday 2⁄3 of the team practiced, Tuesday 7⁄8 , Wednesday 1⁄2 , and Thursday 3⁄4 . On which day were the mostteam members pre

Murljashka [212]

The answer to this question is Tuesday.

7 0

3 years ago