Is the point (2,3) a solution for the inequality y<2x+10

Mathematics

1 answer:

Gnom [1K]3 years ago

8 0

Yes. That point is in the solution space.

_____
You can also figure out algebraically whether the point satisfies the inequality
y < 2x + 10
Substitute the numbers
3 < 2·2 + 10
3 < 14 . . . . . . . . . . . True. (2, 3) is a solution

You might be interested in

paul worked 50 hours last week. if he earns $10 per hour plus time-and-a-half for any hours worked beyond 40 in a week, how much

quester [9]

Answer: 4150

Step-by-step explanation:

You take the 50, becuse the amount earned increases once you surpass 40 you do 40 x 10 and that = 4000 then you take the remaining 10 and times that by 15 (becuse after 40 it is 1.5 of what you where earning before you hit 40 hours and half of ten is 5 so you do 10 plus 5 and times that by 10) then add both numbers together and you have 4150! Hope that helped!

5 0

3 years ago

3⋅ 3/5 (3/5 is a fraction)

LUCKY_DIMON [66]

Well its a simplest form of zero and 6 tenths and if u divide it by 2 youll get 3/5 as a fraction

6 0

4 years ago

How do you write this in standard form? (6-7i)/(1-2i)

xenn [34]

$\frac { \left( 6-7i \right) }{ \left( 1-2i \right) } \cdot 1\\ \\ =\frac { \left( 6-7i \right) }{ \left( 1-2i \right) } \cdot \frac { \left( 1+2i \right) }{ \left( 1+2i \right) } \\ \\ =\frac { 6+12i-7i-14{ i }^{ 2 } }{ 1+2i-2i-4{ i }^{ 2 } }$

$\\ \\ =\frac { 6+5i-14\left( -1 \right) }{ 1-4\left( -1 \right) } \\ \\ =\frac { 6+5i+14 }{ 1+4 } \\ \\ =\frac { 20+5i }{ 5 } \\ \\ =\frac { 20 }{ 5 } +\frac { 5i }{ 5 } \\ \\ =4+i$

8 0

3 years ago

Please help! I have no clue what im doing

prohojiy [21]

Answer:

y = -2x + 1

Step-by-step explanation:

So, first you can use rise over run between the two points to find the slope.

This will get you -6/3, which you can simplify to -2

Then, see where the y intercept is, which is at (0, 1)

The equation will be y = -2x + 1

4 0

3 years ago

Read 2 more answers

Q16. Find x^2 + 1/x^2 , if x + 1/x = 3

erica [24]

Answer:

$2 \times x \times \frac{1}{x} = 2 \\ {x}^{2} + {y }^{2} + 2xy = {(x + y)}^{2} \\ {x}^{2} + \frac{1}{ {x}^{2} } + 2 = {(x + \frac{1}{x} })^{2} = {3}^{2} = 9$

8 0

3 years ago