Classify this triangle by its sides and angles.

Find the value of y so that WX is perpendicular to YZ

Alexxandr [17]

step 1

Find out the slope WX

W(2,-3) and X(-4,9)

m=(9+3)/(-4-2)

m=12/-6

m=-2

step 2

Find out the slope YZ

Y(5,y) and Z(-1,1)

m=(1-y)/(-1-5)

m=(1-y)/-6

m=(y-1)/6

step 3

Remember that

If two lines are perpendicular

then

their slopes are negative reciprocal

that means

(y-1)/6=1/2 -----> because the negative reciprocal of -2 is 1/2

solve for y

2y-2=6

2y=6+2

2y=8

8 0

1 year ago

Which one is rong <br> Scenario <br> Equation <br> Graph or<br> Table

a_sh-v [17]

I believe the equation is wrong

7 0

3 years ago

Find an expression which represents the difference when (-5x-y) is subtracted from (9x+2y) in simplest terms.

AnnyKZ [126]

Answer:

4x+y add like terms ... -5+9=4 and -y(or -1)+2y=y

4 0

2 years ago

A data set with a mean of 34 and a standard deviation of 2.5 is normally distributed

tresset_1 [31]

Answer:

a) $z= \frac{34-34}{2.5}= 0$

$z= \frac{39-34}{2.5}= 2$

And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %

b) $P(X$

$z= \frac{31.5-34}{2.5}= -1$

So one deviation below the mean we have: (100-68)/2 = 16%

c) $z= \frac{29-34}{2.5}= -2$

$z= \frac{36.5-34}{2.5}= 1$

For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%

Step-by-step explanation:

For this case we have a random variable with the following parameters:

$X \sim N(\mu = 34, \sigma=2.5)$

From the empirical rule we know that within one deviation from the mean we have 68% of the values, within two deviations we have 95% and within 3 deviations we have 99.7% of the data.

We want to find the following probability:

$P(34 < X$

We can find the number of deviation from the mean with the z score formula:

$z= \frac{X -\mu}{\sigma}$

And replacing we got

$z= \frac{34-34}{2.5}= 0$

$z= \frac{39-34}{2.5}= 2$

And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %

For the second case:

$P(X$

$z= \frac{31.5-34}{2.5}= -1$

So one deviation below the mean we have: (100-68)/2 = 16%

For the third case:

$P(29 < X$

And replacing we got:

$z= \frac{29-34}{2.5}= -2$

$z= \frac{36.5-34}{2.5}= 1$

For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%

7 0

3 years ago

Can someone pls tell me if this is correct? For the properties, <3 and the bottom one too

saul85 [17]

1. Commutative property of multiplication This is because it represents a*b=b*a
2. Associative property of multiplication. Multiplication problems end with the same product no matter the order of factors.
3. Correct
4. Correct
5. Associative property of addition. Even though the grouping symbols are different, it is equivalent because you are adding all the terms together.
6. Correct

The last one should also be associative property since it applies every time you combine like terms.
Just a reminder: Distributive property is only when you multiply in the form of a(b+c)=ab+ac

7 0

3 years ago