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LenaWriter [7]
2 years ago
13

Please help me if you can please

Mathematics
1 answer:
pychu [463]2 years ago
5 0

Answer:

hello! :) have a good day!

Exact Form:

x= 87/35

Decimal Form:

x= 2.48571428

Mixed Number Form:

x= 2 17/35

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A triangle was dilated by a scale factor of 2. If cos a° = three fifths and segment FD measures 6 units, how long is segment DE?
kiruha [24]

Answer:

10 units

Step-by-step explanation:

Given that:

Cos a = 3 /5

From trigonometry ;

Cos θ = Adjacent / hypotenus

Side Adjacent angle a = 3 = FD

Hypotenus = 5 = DE

3 / 5 = FD / DE

FD = 6 units

3/5 = 6/DE

DE * 3/5 = 6

DE = 6 ÷ 3/5

DE = 6 * 5 /3

DE = 30 /3

DE = 10 units

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2 years ago
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Triple the difference between 32 and 19. A. 3 x (32 -19) B. 32 - 19 x 3 C. 3 x 32-19 D. (3 x 32)-19
Elza [17]
The answer is A 3x(32-19)

Reasoning: Triple the difference of 32 and 19 would be a 3x multiplication of 32-19, you need parenthesis in order to do 32-19 first because of PEMDAS. SO the answer would be 3x(32-19 because none of the other options would show the equation correctly.

If you have any more questions feel free to ask them here on Brainly.com, please make sure to give my answer a rate, like, and vote brainliest if I've helped you out, it helps me a lot too!
5 0
2 years ago
The width of the fountain in Luke's drawing from the example is 2 cm. What is the width of the fountain in Isabella's scale draw
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Answer:

Do you have a image of the fountains, send it to me.and I'll help

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A normal window is constructed by adjoining a semicircle to the top of an ordinary rectangular window, (see figure ) The perimet
Dima020 [189]
Let's find the perimeter of the window.

The bottom side is x. The left and right sides make 2y.
The perimeter of a circle is 2\pi r, so the perimeter of a semicircle must be \pi r, The radius is \frac{1}2x, so that gives \frac{1}2\pi x for the curve. All of that is equal to 12.

x+2y+\frac{1}2\pi x=12

We only want to use one variable to create the area formula, so let's solve for y.

2y=12-x-\frac{1}2\pi x

y=6-\frac{1}2x-\frac{1}4\pi x

Now that we have a value for y in terms of x, we can find the area in terms of x.

The area of the rectangle is going to be xy, which then becomes

A_r=x(6-\frac{1}2x-\frac{1}4\pi x

A_r=6x-\frac{1}2x^2-\frac{1}4\pi x^2

The area of the semicircle is going to be \frac{1}2\pi r^2.

Since r=\frac{1}2x, A_{sc}=\frac{1}2\pi (\frac{1}2x)^2.

A_{sc}=\frac{1}2\pi \frac{1}4x^2

A_{sc}=\frac{1}8\pi x^2

Now let's add the areas of the rectangle and semicircle.

A=A_r+A_{sc}

A=6x-\frac{1}2x^2-\frac{1}4\pi x^2+\frac{1}8\pi x^2

A=6x-\frac{1}2x^2-\frac{1}8\pi x^2

If you wanted to factor out \frac{1}8 like you did, this would become

\boxed{A(x)=\frac{1}8(48x=4x^2-\pi x^2)}

Now what we want to do is find what x is when A is at its highest point, Once we have the value for x we can also find the value for y, of course.

Let's put our equation in the general form of a quadratic.

A(x)=(-\frac{1}2-\frac{1}8\pi )x^2+6x

Now we can use the vertex formula x=\frac{-b}{2a}.
(a and b refer to ax^2+bx+c.)

x=\frac{-6}{2(-\frac{1}2-\frac{1}8\pi)}

x=\frac{-6}{-\frac{1}4\pi -1}

x=\frac{-24}{-\pi -4}

\boxed{x=\frac{24}{\pi +4}}

Now let's plug that in for y=6-\frac{1}2x-\frac{1}4\pi x.

Since our final answers are in decimal form and not exact form, we can make our lives a little easier here and just use x\approx3.36059492.

y\approx6-\frac{1}2(3.36059492)-\frac{1}4\pi(3.36059492)

<span>y\approx6-(1.68029746+2.63940507809)

</span><span>\boxed{y\approx1.68029746191}

Let's take our answers for x and y and round to 2 decimal places.

\boxed{x\approx 3.36\ ft}

\boxed{y\approx 1.68\ ft}</span>
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3 years ago
Write an equation in standard form of the line satisfying the following condition; The line goes through (-2,3), and is horizont
Katen [24]
Slope is 0, b=3

The equation is y=0x+3, or y=3
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3 years ago
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