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vivado [14]
3 years ago
7

I need help with this

Mathematics
1 answer:
dybincka [34]3 years ago
3 0
The last one is 1 I believe
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Complete he statement below. Then use a number line to find the sum 5 + ( -4 )
skad [1K]

Answer:

The statement is 6 in the negative direction

5 + (-4) = 1

Step-by-step explanation:

7 0
3 years ago
Write the number with the least value using the digits 1 through 9.use each digit only once.
amm1812
It would be 123,456,789 (if not counting decimals)

decimals would be like 0.123456789
8 0
3 years ago
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<img src="https://tex.z-dn.net/?f=2%20%5Ctimes%202" id="TexFormula1" title="2 \times 2" alt="2 \times 2" align="absmiddle" class
EastWind [94]
4 (i literally had to think about this cause i thought it was too easy )
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3 years ago
Find c if m A = 70.6°, b = 10.4 in
nata0808 [166]

Answer:

its 7.8

Step-by-step explanation:

4 0
2 years ago
Show that the relation R consisting of all pairs(x, y)such that x and y are bit strings of length three or more that agree in th
Mice21 [21]

Answer:

See proof below

Step-by-step explanation:

An equivalence relation R satisfies

  • Reflexivity: for all x on the underlying set in which R is defined, (x,x)∈R, or xRx.
  • Symmetry: For all x,y, if xRy then yRx.
  • Transitivity: For all x,y,z, If xRy and yRz then xRz.

Let's check these properties: Let x,y,z be bit strings of length three or more

The first 3 bits of x are, of course, the same 3 bits of x, hence xRx.

If xRy, then then the 1st, 2nd and 3rd bits of x are the 1st, 2nd and 3rd bits of y respectively. Then y agrees with x on its first third bits (by symmetry of equality), hence yRx.

If xRy and yRz, x agrees with y on its first 3 bits and y agrees with z in its first 3 bits. Therefore x agrees with z in its first 3 bits (by transitivity of equality), hence xRz.

5 0
3 years ago
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