A(-7,-4) B(-2,0)
√[(x'-x)^2+(y'-y)^2]
√(-2-(-7)^2+(0-(-4)^2
√(5^2)+(4^2)
√25+16
√41
the distance is approximately 6.4 units
Answer:
x=2
Step-by-step explanation:
When you sub in these values for the pythagorean theorem you get 1.5^2+x^2=2.5^2
2.25+x^2=6.25
4=x^2
x=2
AC is the hypotenuse of triangle ABC.
Because the length is 6√2 and angle A is 45 degrees, we know the length of both sides is 6.
This means AB is 6, which it the hypotenuse of triangle BCD.
Using cos(angle) = adjacent leg / hypotenuse we can find x:
cos(60) = X / 6
x = 6 * cos(60)
x = 3
The area of the polygon is 25.5 square units
<h3>How to determine the area of the polygon?</h3>
From the figure, we have the following coordinates
A = (-2, 1)
B = (3, 2)
C = (5, -3)
D = (-1, -3)
The area of the polygon is then calculated as:
A = 0.5 * |(x1y2 - x2y1) + (x2y3 - x3y2) + (x3y4 - x4y3) + (x4y1 - x1y4)|
Substitute the known values in the above equation
Area = 0.5 * |(-2 * 2 - 3 * 1) + (3 * -3 - 5 * 2) + (5 * -3 + 1 * -3) + (-1 * 1 + 2 * -3)|
Evaluate the sum of products
Area = 0.5 * |-51|
Remove the absolute bracket
Area = 0.5 * 51
Evaluate the product
Area = 25.5
Hence, the area of the polygon is 25.5 square units
Read more about areas at:
brainly.com/question/25292087
#SPJ1
Answer:
excuse me these words are some other language
