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Sedaia [141]
2 years ago
9

Bidmass Working out brackets

Mathematics
1 answer:
andreyandreev [35.5K]2 years ago
8 0

Answer:

27 hope it helps you,.................

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Find the slope of the line contain the given pair of points (-6,4) and (1,0)
EastWind [94]
(-6,4) \\
x_1=-6 \\
y_1=4 \\ \\
(1,0) \\
x_2=1 \\
y_2=0 \\ \\
\hbox{the slope}=\frac{y_2-y_1}{x_2-x_1}=\frac{0-4}{1-(-6)}=\frac{-4}{1+6}=-\frac{4}{7}

The slope is -4/7.
8 0
3 years ago
Read 2 more answers
Find two integers whose sum is -10 and product is 16<br> TWO INTERGES PLEASE
Lady bird [3.3K]

Answer:

-2 and -8

Step-by-step explanation:

-2 + (-8) = -10

-2 * -8 = 16

8 0
3 years ago
Pls help, pls just only tell me how to solve
sladkih [1.3K]

To find f(2), look and see where the line crosses the Y axis, when The line is on X 2.


The line is on Y = -2, so the answer would be -2.

5 0
3 years ago
Question number 8. Prove that 3 + √5 is an irrational number.​
Marina86 [1]

Answer :

Let's assume the opposite of the statement i.e., 3 + √5 is a rational number.

\\  \sf \: 3 +  \sqrt{5}  =  \frac{a}{b}   \\  \\   \qquad \: \tiny \sf{(where \:  \: a \:  \: and \:  \: b \:  \: are \:  \: integers \:  \: and \:  \: b \:  \neq \: 0)} \\

\\  \sf \:  \sqrt{5}  =  \frac{a}{b}  - 3 =  \frac{a - 3b}{b}  \\

Since, a, b and 3 are integers. So,

\\ \sf \:  \frac{p - 3b}{b}  \\  \\  \qquad \tiny \sf{ \: (is \:  \: a \:  \: rational \:  \: number \:) } \\

Here, it contradicts that √5 is an irrational number.

because of the wrong assumption that 3 + √5 is a rational number.

\\

Hence, 3 + √5 is an irrational number.

7 0
3 years ago
18 is 25% of what number? A) 36
Nezavi [6.7K]

Answer:

c) 72

Step-by-step explanation:

multiply 18 by 4

5 0
3 years ago
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