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Sedaia [141]
2 years ago
9

Bidmass Working out brackets

Mathematics
1 answer:
andreyandreev [35.5K]2 years ago
8 0

Answer:

27 hope it helps you,.................

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If c is a number with no exponent, what is the value of c in the equation below?
Aleksandr [31]

Answer:

I cant help because its rly blurry but I think the answer is 120¿

4 0
2 years ago
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PLZ hurry, 20 points for simple Q: Solve 5x + 1 = 2x2 + 9x.
iragen [17]
The answer is:
 
a: 1 = 2(x^2<span> + 2</span>x<span>) 
b:</span>1 = 2x^2 + 4<span>x
d:</span>3 = 2(x + 1)^2

you can tell these are your answer when you solve it.
Hope this helps!
8 0
3 years ago
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Make a number that has a 6 that is 10 times the value of the digit 6 in 165,438 Comparing digits in whole numbers
Ipatiy [6.2K]

Answer:

An example of such number is 1,645,378 ( The value of 6 here is 600,000)

Step-by-step explanation:

Here, we want to compare digits in whole

numbers.

The value of 6 in 165,438 = 60,000

Now, we want a number that is 10 times the value of 6 here

10 times the value of 6 here will be 10 * 60,000 = 600,000

So we want a number which has the value of 6 in it as 600,000

The number in this case as an example can be ;

1,645,378

3 0
3 years ago
What is 14 ten thousands+12 thousands
timurjin [86]
The answer to this question is 152,000!
4 0
3 years ago
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F(x) = x + 4 and g(x) = 2x + 3, evaluate each expression.
Rom4ik [11]

Answer:

15.~f(g(2))=\Large\boxed{11}\\

16.~g(f(2.5))=\Large\boxed{16}

17.~g(f(-5))=\Large\boxed{1}

18.~f(g(-5))=\Large\boxed{-3}

Step-by-step explanation:

<h3>Given information</h3>

f(x)=x+4

g(x)=2x+3

<h3>Question 15. f(g(2))</h3>

<u>Substitute values into the first function</u>

g(2)=2(2)+3

g(2)=4+3

g(2)=7

<u>Substitute the values of the first function into the second</u>

f(g(2))=f(7)

f(7)=(7)+4

f(7)=\Large\boxed{11}

<h3>Question 16. g(f(2.5))</h3>

<u>Substitute values into the first function</u>

f(2.5)=(2.5)+4

f(2.5)=6.5

<u />

<u>Substitute the values of the first function into the second</u>

g(f(2.5))=g(6.5)

g(6.5)=2(6.5)+3

g(6.5)=13+3

g(6.5)=\Large\boxed{16}

<h3>Question 17. g(f(-5))</h3>

<u>Substitute values into the first function</u>

f(-5)=(-5)+4

f(-5)=-1

<u>Substitute the values of the first function into the second</u>

g(f(-5))=g(-1)

g(-1)=2(-1)+3

g(-1)=-2+3

g(-1)=\Large\boxed{1}

<h3>Question 18. f(g(-5))</h3>

<u>Substitute values into the first function</u>

g(-5)=2(-5)+3

g(-5)=-10+3

g(-5)=-7

<u>Substitute the values of the first function into the second</u>

f(g(-5))=f(-7)

f(-7)=(-7)+4

f(-7)=\Large\boxed{-3}

Hope this helps!! :)

Please let me know if you have any questions

7 0
1 year ago
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