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ki77a [65]
2 years ago
13

Quadrilateral GHand JK has vertices G(2, 3), H(8, 2), J(6, 8), K(3, 6). It is transformed according to the rule T(–4, –5). What

are the coordinates of G
Mathematics
1 answer:
Shkiper50 [21]2 years ago
4 0
(2,-3) because the 3 becomes a negative when transforming.
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1. Consider the subtraction expression 9 + (–10) on the number line shown. Explain how you would evaluate the expression on the
ExtremeBDS [4]

Answer:

The answer is B: Begin at 9 and move 10 units to the left.

Step-by-step explanation:

If you move to the left on a number line, you are subtracting. If you move to the right, you are adding. If you add -10 to a number, you are, in other words, subtracting 10 from the number.


5 0
3 years ago
Read 2 more answers
Solve: <br> 8x-5y=11 4x-3y=5
Schach [20]

Answer:

y is 1 and x is 2

Step-by-step explanation:

please mark me as brainliest!!<3

5 0
2 years ago
PLS HELP ASAP WILL MARK BRAINLIST !!! (If its right, might have to wait a day or to cause i have to see if its right)
fiasKO [112]

Answer:

1)y=3x-2

2)y=x-4

Step-by-step explanation:

1)As we know slope intercept from

y=mx-b

y=3/1x-2

y=3x-2

2)y=mx-b

y=1x-4

  y=x-4

4 0
3 years ago
Read 2 more answers
-x=-y+2 and 3y+4=2x solve using matrices
MissTica

\begin{cases}-x=-y+2\\3y+4=2x\end{cases}\implies\begin{cases}x-y=-2\\2x-3y=4\end{cases}

In matrix form, this is

\begin{bmatrix}1&-1\\2&-3\end{bmatrix}\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}-2\\4\end{bmatrix}

The coefficient matrix has determinant

\begin{vmatrix}1&-1\\2&-3\end{vmatrix}=-3+2=-1\neq0

so it has an inverse, which is

\begin{bmatrix}1&-1\\2&-3\end{bmatrix}^{-1}=\begin{bmatrix}3&-1\\2&-1\end{bmatrix}

Multiply both sides by the inverse matrix:

\begin{bmatrix}3&-1\\2&-1\end{bmatrix}\begin{bmatrix}1&-1\\2&-3\end{bmatrix}\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}3&-1\\2&-1\end{bmatrix}\begin{bmatrix}-2\\4\end{bmatrix}

\implies\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}-10\\-8\end{bmatrix}

so that x=-10 and y=-8.

8 0
3 years ago
D=a+b+c solve for b<br> I need some help
Hoochie [10]

Hi Walker


d=a+b+c

Flip

a+b+c=d

Add -a to both sides

a+b+c-a=d-a

b+c=-a+d

Now add -c to both sides

b+c-c=-a+d-c

b= -a-c+d


I hope that's help:0

4 0
2 years ago
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