Area of the sector = 1/2 * r^2 * theta where theta is the angle subtended by the arc at the center ( in radians)
In this case m < theta = 360 - 235 = 125 degrees or 2.182 radians
So, the area of shaded area = 1/2 * 20^2 * 2.182 = 436.4 in^2
Answer:
WX = WZ
Step-by-step explanation:
Given
See attachment for triangles
Required
Additional information to prove the congruence of the triangles
Congruence by SAS means 1 angle and 2 sides of each triangles are equal.
The mark on angle W means that <XWY = <ZWY--- This represent the A in SAS
Both triangles share line WY.
So, WY = WY
Lastly, to complete the proof, lines WX must equal line WZ
Answer:
The side s has a length of 4 and side q has a length of 4
⇒ F
Step-by-step explanation:
In the 30°-60°-90° triangle, there is a ratio between its sides
side opp (30°) : side opp (60°) : hypotenuse
1 :
: 2
In the given triangle
∵ The side opposite to 30° is s
∵ The side opposite to 60° is q
∵ The hypotenuse is 8
→ Use the ratio above to find the lengths of s and q
side opp (30°) : side opp (60°) : hypotenuse
1 :
: 2
s : q : 8
→ By using cross multiplication
∵ s × 2 = 1 × 8
∴ 2s = 8
→ Divide both sides by 2
∴ s = 4
∴ The length of s is 4
∵ q × 2 =
× 8
∴ 2q = 8
→ Divide both sides by 2
∴ q = 4
∴ The length of q is 4
F(x) = 2x - 4
f(2 ≤ x) = 2(2 ≤ x) - 4
f(x ≥ 2) = 2(x ≥ 2) - 4
f(x ≥ 2) = 2(x) ≥ 2(2) - 4
f(x ≥ 2) = 2x ≥ 4 - 4
f(x ≥ 2) = 2x ≥ 0
f(x ≥ 2) = x ≥ 0
f(x) = 2x - 4
f(x ≤ 6) = 2(x ≤ 6) - 4
f(x ≤ 6) = 2(x) ≤ 2(6) - 4
f(x ≤ 6) = 2x ≤ 12 - 4
f(x ≤ 6) = 2x ≤ 8
f(x ≤ 6) = x ≤ 4
Vertex form of a parabola
<span>y = a (x - h)^2 + k </span>
<span>where (h, k) is the vertex </span>
Substituting the values of h and k.
we get,
<span>y = a(x + 4)^2 + 2 </span>
<span>substituting in the point (0, -30) for x and y
</span><span>-30 = a (0 + 4)^2 + 2
</span>solve for a,
<span>-30 = 16 a + 2 </span>
<span>-32 = 16 a </span>
<span>-2 = a </span>
<span>y = -2(x + 4)^2 + 2 </span>
<span>Put y = 0 </span>
<span>-2 x^2 - 16 x - 30 = 0 </span>
<span>-2(x^2 + 8 x + 15) = 0 </span>
<span>x^2 + 8 x + 15 = 0 </span>
<span>(x + 3)(x + 5) = 0 </span>
<span>x = -3
x = -5</span>