15-k. K=Kelsy.
9d. D=doughnuts purchased
23+e. E=elaina's earnings
Answer:
The area of the Iris is 4 times greater.
Step-by-step explanation:
Firstly, we have to realize that we cannot solve this problem without knowing the radius of the iris. because from the information given, the radius of the iris could well be the size of the galaxy and contract from width of 4mm to 2mm and we wouldn't know!
The average radius of the iris is 6mm, so we take this value.
Now, initially the width of the iris is 4mm, that means the radius of the pupil is:

Therefore it's area
is:

When the iris contracts to 2mm, the radius of the pupil becomes:

Then it's area is
:

To find how many times greater this final area is than the initial area, we just divide it by the initial area:

This is 4 times greater than the initial area.
Answer:
For the first question, he would raise $38.
Step-by-step explanation:
1 x 12 = $12
2 x 13 = $26
12 + 26 = $38
Frist we need to find the mean of both so
1.55
2.67
then we make a number graph and see how mant place does it take to get to them from 0 67and55/by them selfs = 1.2(rounded)
1.2 is you answer
Answer:
QR = 65.4 m
Step-by-step explanation:
a. Apply Law of Cosines to find QR:
p² = q² + r² - 2qr × Cos P
p = QR = ?
q = PR = 150 m
r = PQ = 120 m
P = 25°
Plug in the values
p² = 150² + 120² - (2)(150)(120) × Cos(25°)
p² = 22,500 + 14,400 - 36,000 × 0.9063
p² = 36,900 - 32,626.8
p² = 4,273.2
p = √4,273.2
p ≈ 65.4 m (nearest tenth)
QR = 65.4 m