PLS PLS PLS HELP I DONT HAVE MUCH TIME FOR THIS! I WILL MARK BRAINLIEST AND 22 POINTS!
2 answers:
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Answer:
There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by
After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.
In this problem
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so .
What is the probability that a line width is greater than 0.62 micrometer?
That is
So
Z = 2.4 has a pvalue of 0.99180.
This means that P(X \leq 0.62) = 0.99180.
We also have that
There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Hi there!
First we need to work out the parenthesis, which can for instance be done using rainbow technique.
Now subtract 3 from both sides.
And finally add 3x to both sides.
The 4th answer choice is correct.
First we need to work out the parenthesis, which can for instance be done using rainbow technique.
Now subtract 3 from both sides.
And finally add 3x to both sides.
The 4th answer choice is correct.
Answer:
Step-by-step explanation:
Given that,
The sum of first n term of a sequence is
We need to find the sum of the first 5 terms.
Put n = 5,
So, the sum of first 5 terms is equal to .