The distance of segment AX sis found to be 8.6 units using the distance formula.
<h3>What exactly is the distance formula?</h3>
is the distance formula. This works for any two points in two-dimensional space with coordinates (x₁, y₁) for the first and (x₂, y₂) for the second. - You may easily remember it if you remember that it is Pythagoras' theorem, that the distance is the hypothenuse, and that the coordinate lengths are the difference between the x and y components of the points.
<h3>Why do we employ the distance formula?</h3>
- In complex numbers, the distance formula is used to express the plane and its magnitude.
- Furthermore, distance formulae can be used to calculate the distance between two planes in three-dimensional or n-dimensional planes. It is also used to calculate the magnitude formula.
Given: A(-4, 5), X (1, −2)
We need to find the distance of the segment AX.
Distance of AX is given as :
![\sqrt{[1-(-4)]^{2} + [-2-5]^{2} } \\= \sqrt{25 + 49}\\ = \sqrt{74}\\ =8.6](https://tex.z-dn.net/?f=%5Csqrt%7B%5B1-%28-4%29%5D%5E%7B2%7D%20%2B%20%5B-2-5%5D%5E%7B2%7D%20%20%7D%20%5C%5C%3D%20%5Csqrt%7B25%20%2B%2049%7D%5C%5C%20%3D%20%5Csqrt%7B74%7D%5C%5C%20%3D8.6)
Therefore, the distance of segment AX sis found to be 8.6 units using the distance formula.
Learn more about distance formula here:
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Answer:
m = -2.5
b = 5
Step-by-step explanation:
y = mx + b
Answer:
7 units down
Step-by-step explanation:
x+4
x-3
4-(-3) =7
Answer:
y=-6
Step-by-step explanation:
3y+7=-11
3y=-11-7
3y=-18
y=-18/3
y=-6