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Akimi4 [234]
3 years ago
6

What is the quotient оf (x^3 + 3x^2– 4x– 12)-(х^2 + 5х+6)?

Mathematics
2 answers:
balandron [24]3 years ago
5 0
The quotient would be (x-2)
DIA [1.3K]3 years ago
3 0

Answer:

The quotient is (x-2)

Step-by-step explanation:

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63-47 using mental math​
Anettt [7]

Answer:

63 - 47 equals 16

7 0
3 years ago
Read 2 more answers
Find the miing value in the ratio table. Then write the equivalent ratio. Plum 14 42 Grape 7 3 24 The equivalent ratio are 14 :
denis-greek [22]

The equivalent ratio is 8 : 4.

And the missing values are as follows 21, 6 and 48.

Complete table be,

Plum     14   42   6   48

Grape    7    21    3    24

Given, a ratio table

Plum     14   42   __   __

Grape    7    __    3    24

we have to find the missing values and the equivalent ratios.

in the first ratio,

Plum : Grape = 14 : 7 = 2 : 1

Now, in the second ratio,

2 : 1 = 42 : __

x = 21

Now, in the third ratio,

2 : 1 = __ : 3

x = 6

Now, in the forth ratio,

2 : 1 = __ : 24

x = 48

So, the equivalent ratio is 8 : 4.

And the missing values are as follows 21, 6 and 48.

Hence, the equivalent ratio is 8 : 4.

And the missing values are as follows 21, 6 and 48.

Complete table be,

Plum     14   42   6   48

Grape    7    21    3    24

Learn more about Ratios and Proportions here brainly.com/question/26974513

#SPJ4

4 0
1 year ago
Someone fr i,end request me pls
Greeley [361]

Answer:

whaaaat dooooo youuuuu mean dear

5 0
2 years ago
What is the coefficient of a3 after simplifying this expression? 2a3−10ab2+3a3−ab2−7
Sergio [31]

Answer:

<h3>5</h3>

Step-by-step explanation:

Given the expression

2a^3−10ab^2+3a^3−ab^2−7

We are to find the coefficient of a^3

First is to collect the like terms;

2a^3−10ab^2+3a^3−ab^2−7

= 2a^3+3a^3−10ab^2−ab^2−7

= 5a^3-11ab^2-7

From the resulting equation, you can see that the coefficient of the term having a^3 is 5

7 0
3 years ago
Help with 21 would be much appreciated.
umka2103 [35]

Answer:

\large\boxed{x=2\sqrt{21}\ and\ y=4\sqrt3}

Step-by-step explanation:

Look at the picture.

ΔADC and ΔCDB are similar. Therefore the sides are in proportion:

\dfrac{AD}{CD}=\dfrac{CD}{DB}

We have

AD=14-8=6\\CD=y\\DB=8

Substitute:

\dfrac{6}{y}=\dfrac{y}{8}         <em>cross multiply</em>

y^2=(6)(8)

y^2=48\to y=\sqrt{48}\\\\y=\sqrt{16\cdot3}\\\\y=\sqrt{16}\ cdot\sqrt3\\\\\boxed{y=4\sqrt3}

For x use the Pythagorean theorem:

x^2=6^2+(4\sqrt3)^2\\\\x^2=36+48\\\\x^2=84\to x=\sqrt{84}\\\\x=\sqrt{4\cdot21}\\\\x=\sqrt4\cdot\sqrt{21}\\\\\boxed{x=2\sqrt{21}}

3 0
3 years ago
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