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3 years ago

F(x)=(2x-1)(x-5) find all zeros

Mathematics

2 answers:

Sergio039 [100]3 years ago

7 0

Answer:

x = 5 and x = $\frac{1}{2}$

Step-by-step explanation:

To find the zeros equate f(x) to zero, that is

(2x - 1)(x - 5) = 0

equate each factor to zero and solve for x

2x - 1 = 0 ⇒ x = $\frac{1}{2}$

x - 5 = 0 ⇒ x = 5

Stels [109]3 years ago

6 0

Answer:

x = 5 ,, x = 1/2

Step-by-step explanation:

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3 years ago

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Answer:

Step-by-step explanation:

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4 years ago

5. Find the solutions of x^2 – X-30 = 0.<br><br> please show work on how to do it

erica [24]

Answer:

x=6, x= -5

Step-by-step explanation:

Factor the equation

x^2 - x - 30 = 0 ----> (x-6)(x+5)=0

Next find the solution by setting those in the paranthesis equal to zero.

x-6=0 ----> x= 6

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8 0

3 years ago

Read 2 more answers

F(x)=x-1/x^2-x-6 which is the graph of

hoa [83]

Answer:

The graph is attached below.

Step-by-step explanation:

<em>As you have not added the graph, so I will be solving the function for a graph.</em>

Given the function

$f\left(x\right)=x-\frac{1}{x^2}-x-6$

$x-\mathrm{axis\:interception\:points\:of\:}-\frac{1}{x^2}-6:$

$\mathrm{x-intercept\:is\:a\:point\:on\:the\:graph\:where\:}y=0$

$-\frac{1}{x^2}-6=0$

$-1-6x^2=0$

$\mathrm{No\:Solution\:for}\:x\in \mathbb{R}$

$\mathrm{No\:x-axis\:interception\:points}$

$y-\mathrm{axis\:interception\:point\:of\:}-\frac{1}{x^2}-6:$

$y\mathrm{-intercept\:is\:the\:point\:on\:the\:graph\:where\:}x=0$

As we know that the domain of a function is the set of input or argument values for which the function is real and defined.

$\mathrm{Domain\:of\:}\:-\frac{1}{x^2}-6\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x0\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:0\right)\cup \left(0,\:\infty \:\right)\end{bmatrix}$

$\mathrm{Since}\:x=0\:\mathrm{is\:not\:in\:domain}$

$\mathrm{No\:y-axis\:interception\:point}$

$\mathrm{Asymptotes\:of}\:-\frac{1}{x^2}-6:\quad \mathrm{Vertical}:\:x=0,\:\mathrm{Horizontal}:\:y=-6$

$\mathrm{Range\:of\:}-\frac{1}{x^2}-6:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)$

The graph is attached below.

5 0

3 years ago