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babymother [125]
3 years ago
13

100 points answer the questions

Mathematics
2 answers:
ludmilkaskok [199]3 years ago
6 0

Answer:

the is no info

Step-by-step explanation:

V125BC [204]3 years ago
4 0

Answer:

100 points

Step-by-step explanation:

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Assuming the pattern continues, what are the next two terms in this
pshichka [43]
D. 53, 107
The pattern is multiplying the previous number by two and then adding one to it.
4 0
4 years ago
What is the sum of the fractions 3over5 +7/5
WINSTONCH [101]

Answer:

2 is the answer

Step-by-step explanation:

3/5+7/5

3+7/5( if the denomeneter are same we can write one number )

10/5

2 is the answer ( divide both numbers by 5)

Hope it is helpful for you

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3 0
3 years ago
What is an equation of the line, in point-slope form, that passes through the given point and has the given slope? point: (8,-8)
creativ13 [48]
Point slope is y-y1= m(x-x1) where m is slope

Plug the values in:
y-(-8)=3(x-8)

Simplify:
y+8=3(x-8)
3 0
4 years ago
Rachel uses 75 inches of ribbon to make 4 bows. She uses the same amount of ribbon to make each bow. 1 foot = 12 inches 1 yard =
olasank [31]

Answer: 6.25 yards

Step-by-step explanation:

75 inches = 4 bows

To get 12, you have to multiply 4 by 3. Therefore, you also have to multiply 75 by 3.

75*3 is 225.

225 inches = 12 bows

225 inches is 6.25 yards. Hope this helps :)

5 0
3 years ago
Nate tosses a ball up a hill for his dog to chase. The path of the ball is modeled by the function y = –14x2 + 335x, where x is
tankabanditka [31]

Answer:

The horizontal distance the ball travels before it hits the ground is 22.\overline{857142} feet

Step-by-step explanation:

The given parameter are;

The function modelling the path of the ball tossed by Nate y = -14·x² + 335·x

x = The horizontal distance the ball travels from Nate in feet

y = The height of the ball in feet

The line equation modelling the hill is y = 15·x

The point where the ball hits the ground is given by the point the graph of the equation for the path of the ball and the path of the model of the line of the hill meet as follows;

Ball path is y = -14·x² + 335·x

Hill path is y = 15·x

The point both paths meet and the ball hits the ground is -14·x² + 335·x = 15·x

Which gives;

-14·x² + 335·x - 15·x = 0

-14·x² + 320·x = 0

320·x - 14·x² = 0

x × (320 - 14·x) = 0

x = 0, or x = 320/14 = 22 6/7 = 22.\overline{857142} feet

Therefore;

The horizontal distance the ball travels before it hits the ground = x = 22.\overline{857142} feet.

3 0
3 years ago
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