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2 years ago

What is the property 389•0=0

Mathematics

1 answer:

Ghella [55]2 years ago

6 0

Multiplication Property of Equality, i'm pretty sure is your answer you are not very clear in the question

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Solve this system of equations: What is the value of x?

Ipatiy [6.2K]

Answer:

Step-by-step explanation:

Substitute y=2x in the first equation into the second.

The second equation then becomes;

x = -(2x)+6

x = -2x+6

Collectiing like terms, more -2x to the left,

x+2x =6

3x=6

x= $\frac{6}{3}$

x= 2

7 0

2 years ago

The picture shows a circular clock face.

marysya [2.9K]

Answer:

[C] 25π square inches

Step-by-step explanation:

Given that:

the long hand of the clock is about 5 inches long.

To Find:

What is the approximate area of the clock face?

Solve:

Formula - A =πr²

Note that;

π = 3.14 (about)

Radius - 5 inches

A =πr²

A = 3.14(5)²

A = 3.14(25)

A = 78.5

Now let see the answer choices:

A. 5π square inches ≈ 5(3.14) = 15.7

B. 10 π square inches ≈ 10(3.14) = 31.4

C. 25 π square inches ≈ 25(3.14) = 78.5

D. 100 π square inches ≈ 100(3.14) = 314

Hence, the answer is [C] 25 π square inches

Kavinsky~

6 0

1 year ago

Read 2 more answers

Gary earns $12 an hour plus $16 an hour for every hour of overtime. Overtime hours are any hours more than 30 hours for the week

hoa [83]

Part A.

Amount of money earned = Regular rate per hour * Number of working hours

M = 12 x

Part B.

Amount of wages earned = Regular rate per hour * Maximum number of regular working hours + Overtime rate per hour * Excess working hours

T = 12 * 30 + 16 * y

T = 360 + 16 y

T = 16 y + 360

Part C.

Given T = 408, find y:

408 = 16 y + 360

y = 3 hrs

Therefore the total hours Gary worked that week is,

x + y = 30 + 3 = 33 hrs

(x = 30 since that is the maximum limit for regular working hours)

7 0

2 years ago

1-s=6-6s help meeeeeee

earnstyle [38]

5=-7s
5/-7
You're welcome

3 0

2 years ago

Find the points on the curve where the tangent is horizontal or vertical. If you have a graphing device, graph the curve to chec

klasskru [66]

Answer:

There is a horizontal tangent at (0,-4)

The tangent is vertical at (-2,-3) and (2,-3).

Step-by-step explanation:

The given function is defined parametrically by the equations:

$x=t^3-3t$

and

$y=t^2-4$

The tangent function is given by:

$\frac{dy}{dx}=\frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

$\implies \frac{dy}{dx}=\frac{2t}{3t^2-3}$

The tangent is vertical at when $\frac{dx}{dt}=0$

$\implies \frac{3t^2-3}{2t}=0$

$\implies 3t^2-3=0$

$\implies 3t^2=3$

$\implies t^2=1$

$\implies t=\pm1$

When t=1,

$x=1^3-3(1)=-2$ and $y=1^2-4=-3$

When t=-1,

$x=(-1)^3-3(-1)=2$ and $y=(-1)^2-4=-3$

The tangent is vertical at (-2,-3) and (2,-3).

The tangent is horizontal, when $\frac{dy}{dx}=0$ or $\frac{dy}{dt}=0$

$\implies 2t=0$

$\implies t=0$

When t=0,

$x=0^3-3(0)=0$ and $y=0^2-4=-4$

There is a horizontal tangent at (0,-4)

5 0

2 years ago