Answer:
B
Step-by-step explanation:
Given a quadratic equation in standard form
ax² + bx + c = 0 ( a ≠ 0 )
Then the discriminant is
Δ = b² - 4ac
• If b² - 4ac > 0 then 2 real irrational roots
• If b² - 4ac > 0 and a perfect square then 2 real rational roots
• If b² - 4ac = 0 then 1 real double root
• If b² - 4ac < 0 then 2 complex roots
Given
x² + 3x - 7 = 0 ← in standard form
with a = 1, b = 3, c = - 7 , then
b² - 4ac
= 3² - (4 × 1 × - 7) = 9 + 28 = 37
Since b² - 4ac > 0 then 2 real irrational roots
You have to find the circumference of both circles.
B= 25.12
Y= 87.92
I think this is right.
Answer:
the last answer is -1 :))))))
Answer:
Step-by-step explanation:
From the question attached,
Given:
RT and PQ intersect at a point S.
RS = PS and ST = SQ
To prove :
RT = PQ
Statements Reasons
1). RS = PS and ST = SQ 1). Given
2). RS + ST = PS + SQ 2). Addition property
3). RS + ST = RT ; PS + SQ = PQ 3). Pair of line segments
4). RT = PQ 4). Substitution property
Answer:
c = 17
Step-by-step explanation:
Use the Pythagorean Theorem to solve this problem.
The equation is a² + b² = c².
"a" and "b" are the length of the two shorter sides or values.
"c" is the length of the longest side or value, also the hypotenuse.
Since we know the two smaller values, we can <u>replace "a" and "b" with 8 and 15</u>. It does not matter which letter you decide to replace with which number.
Then<u> simplify and isolate "c" </u>to find the largest value.
a² + b² = c²
8² + 15² = c² Substitute "a" and "b". Square the numbers to simplify
64 + 225 = c² Add to simplify
289 = c²
√289 = √c² Square root both sides
√289 = c "c" will be isolated because √ and ² are reverse operations
c = √289 Put 'c' on the left side for standard formatting.
c = 17 Answer
Therefore the largest value, c, is 17 in the triple.
