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rewona [7]
3 years ago
11

Please help I'm begging a ACE OR GENES To help me please please help please please ASAP please please help please please ASAP pl

ease please help

Mathematics
1 answer:
Westkost [7]3 years ago
7 0

Answer:

3/2

Step-by-step explanation:

WX/AB = 12/8 = 3/2

Answer: 3/2

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3.(08.01 MC)
nirvana33 [79]

Answer:

4 inches

Step-by-step explanation:

The formula is L=√((3×V)/h)

5 0
3 years ago
Can 100+25 sqrt(2) be simplified?
WINSTONCH [101]

Answer:

No

Step-by-step explanation:

100+25squared +( 2)

This is the answer 135.355339059

This can not be simplified as it is a decimal number!

7 0
3 years ago
Identify the type of figure
Montano1993 [528]

The answer will be option 6. angle.

6 0
3 years ago
Given the triangle below, what is m<br> A. 46.2<br> B. 41.40<br> C. 48.4<br> D. 38.6°
Brrunno [24]

Answer:

B 41.4

Step-by-step explanation:

complete Pythagoras for general triangles :

c² = a² + b² - 2ab×cos(C)

with "c" being the side opposite of the angle C.

=>

8² = 10² + 12² - 2×10×12×cos(C)

64 = 244 - 240×cos(C)

240×cos(C) = 244 - 64 = 180

cos(C) = 180/240 = 18/24 = 3/4 = 0.75

C = 41.40962211... ≈ 41.4

5 0
3 years ago
A three-bedroom house in North Augusta sold for $190,000. If housing prices are expected to increase 1.8% annually in that town,
Ivahew [28]

Answer:

we know that the initial price of the house is $190,000.

We also know that the expected increase is 1.8%, this means that the year zero we have no increase; the price is $190,000.

one year after we have an increase of the 1.8% (or 0.018 in decimal form), this means that the new price is:

$190,000 + $190,000*0.018 = $190,000*(1.018)

another year after, we have:

$190,000*(1.018)*(1.018) = $190,000*(1.018)^2

and etc

The function that models the price as a function of the years, represented as y, is:

P(y) = $190,000*(1.018)^y

If we want to know the price in 5 years, we need to replace y = 5 in the equation:

p(5) = $190,000*(1.018)^5 = $207,726.80

Step-by-step explanation:

hope this helps you

3 0
3 years ago
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